传递来自selecetd选项值的'＆'，在url中

<select name="n" onchange="if(this.selectedIndex != 0) window.location = this.options[this.selectedIndex].value">
  <option value="url&amp;param={param}">
     <xsl:if condition>
       <xsl:attribute name="selected">true</xsl:attribute>
     </xsl:if>
  </option>
</select>

The code above works fine, it passes selected option to url. The only problem is that when the parameter contains '&' sign in between. How do I pass parameter when it's value is something like 'A & B'? urlencode seems not helpful? Thanks for your time!

上面的代码工作正常,它将选定的选项传递给url。唯一的问题是当参数包含'&'之间的符号时。如果参数值为'A&B',我如何传递参数? urlencode似乎没有用?谢谢你的时间!

1 个解决方案

#1

Tried urlencode(), but it returns double escaping error. Note that this question is not about to simply encode the whole url, but to escape some Special Characters for passing parameters. I had another situation, in which a parameter value has '+' sign in the string. I figured that it's probably better to show the string but return a nameid something as the value, which is int. My option value changed to something like this:

尝试了urlencode(),但它返回双重转义错误。请注意,这个问题不是简单地编码整个URL,而是为了传递一些特殊字符来传递参数。我有另一种情况,其中参数值在字符串中有'+'符号。我认为显示字符串可能更好,但返回一个nameid作为值,即int。我的选项值更改为以下内容:

  <select onchange="if(this.selectedIndex != 0) window.location = this.options[this.selectedIndex].value">
    <option value="" selected="selected"><xsl:value-of select="/A/D/NAME"/></option>
    <xsl:for-each select="/A/B/C">                  
     <option value="URL&amp;Name={NAME}&amp;ID={ID}"
      <xsl:if test="NAME=/A/D/NAME"><xsl:attribute name="selected">true</xsl:attribute></xsl:if>
      <xsl:value-of select="NAME"/>
     </option>
    </xsl:for-each>
  </select>

The url now have the Id as the parameter2 matching the parameter1(Name). And I can use this Id to search the database and return the string(Name) to show again. This doesn't directly answer the question, but does provide a workaround.

url现在将Id作为与parameter1(Name)匹配的parameter2。我可以使用此Id来搜索数据库并返回字符串(Name)以再次显示。这并没有直接回答这个问题,但确实提供了一种解决方法。