How would you assign each element of [5, 6, 7] to row's values and make row become {1=>5, 2=>6, 3=>7}?
如何将[5,6,7]的每个元素分配给行的值并使行变为{1 => 5,2 => 6,3 => 7}?
row = {1=>0, 2=>1, 3=>0}
#this following line doesn't work of course
row.values = [5, 6, 7]
#NoMethodError: undefined method `values=' for {1=>0, 2=>1, 3=>0}:Hash
row
#I want: {1=>5, 2=>6, 3=>7}
4 个解决方案
#1
1
row.keys.zip([5, 6, 7]){|kv| row.store(*kv)}
#2
2
A generic solution that works for any length of the array, and makes the index of the element the key in the hash is:
适用于任何数组长度的通用解决方案,并使元素的索引成为哈希中的键:
Hash[row.each_with_index.map {|elem, i| [i, elem]}]
#3
0
array = [5, 6, 7]
Hash[*array.each_with_index.map{ |elem, idx| [idx + 1, elem]}.flatten]
as result
{1=>5, 2=>6, 3=>7}
#4
0
You can try the below:
您可以尝试以下方法:
row = {1=>0, 2=>1, 3=>0}
p Hash[*(row.keys.zip([5, 6, 7]).flatten)]
#=> {1=>5, 2=>6, 3=>7}
#1
1
row.keys.zip([5, 6, 7]){|kv| row.store(*kv)}
#2
2
A generic solution that works for any length of the array, and makes the index of the element the key in the hash is:
适用于任何数组长度的通用解决方案,并使元素的索引成为哈希中的键:
Hash[row.each_with_index.map {|elem, i| [i, elem]}]
#3
0
array = [5, 6, 7]
Hash[*array.each_with_index.map{ |elem, idx| [idx + 1, elem]}.flatten]
as result
{1=>5, 2=>6, 3=>7}
#4
0
You can try the below:
您可以尝试以下方法:
row = {1=>0, 2=>1, 3=>0}
p Hash[*(row.keys.zip([5, 6, 7]).flatten)]
#=> {1=>5, 2=>6, 3=>7}