比较两个列表以搜索常见项目

List<int> one //1, 3, 4, 6, 7
List<int> second //1, 2, 4, 5

How to get all elements from one list that are present also in second list?

如何从第二个列表中的一个列表中获取所有元素？

In this case should be: 1, 4

在这种情况下应该是：1,4

I talk of course about method without foreach. Rather linq query

我当然谈论没有foreach的方法。而是linq查询

2 个解决方案

#1

You can use the Intersect method.

您可以使用Intersect方法。

var result = one.Intersect(second);

Example:

例：

void Main()
{
    List<int> one = new List<int>() {1, 3, 4, 6, 7};
    List<int> second = new List<int>() {1, 2, 4, 5};

    foreach(int r in one.Intersect(second))
        Console.WriteLine(r);
}

Output:

输出：

1
4

1 4

#2

static void Main(string[] args)
        {
            List<int> one = new List<int>() { 1, 3, 4, 6, 7 };
            List<int> second = new List<int>() { 1, 2, 4, 5 };

            var result = one.Intersect(second);

            if (result.Count() > 0)
                result.ToList().ForEach(t => Console.WriteLine(t));
            else
                Console.WriteLine("No elements is common!");

            Console.ReadLine();
        }

#1