Given a string, how can I identify the string has a colon in between a colon and a semi-colon?
给定一个字符串，我如何确定字符串在冒号和分号之间有一个冒号?
For example, I want to identify that the following has a : in between : and ;. If this is the case, I want to replace the colon in the middle.
例如，我想确定以下内容中有:in between: and;如果是这样的话，我想要替换中间的冒号。
background-image: url('http://google.com/img.jpg');"
背景图片:url(http://google.com/img.jpg);”
I can't come up with a regex for the life of me. I can only match the whole url('http://google.com/img.jpg'). What regex can I use that can do this for me?
我无法为我的生活想出一个正则表达式。我只能匹配整个url('http://google.com/img.jpg')。我可以用什么regex为我做这个?
$pattern = '';
$matched = preg_replace($pattern, '|__|', $string);
1 个解决方案
#1
3
$pattern = '/(:.*?):(.*?;)/s';
$matched = preg_replace($pattern, '$1|__|$2', $string);
#1
3
$pattern = '/(:.*?):(.*?;)/s';
$matched = preg_replace($pattern, '$1|__|$2', $string);