正则表达式匹配URL中的单词

I need a regular expression which matches:

我需要一个匹配的正则表达式:

http://example.com/foo
http://example.com/foo/
http://example.com/foo/bar

but not:

http://example.com/foobar

Using http://example.com/foo/? matches the three types, but it matches /foobar too that I don't want. What should I add to the regex to not match /foobar?

使用http://example.com/foo/?匹配这三种类型,但它匹配/ foobar也是我不想要的。我应该在正则表达式中添加什么来匹配/ foobar?

5 个解决方案

#1

Try this one:

试试这个:

^http://example\.com/foo(?:/.*)?$

#2

In your regex, the last /? means an optional / at the end. So /foobar is also matched. Try this:

你的正则表达式,最后/?意味着可选/最后。所以/ foobar也匹配。试试这个:

http:\/\/example\.com\/foo($|\/.*)

#3

Try something like this:

尝试这样的事情:

http://example.com/foo(?:\/|/(\w+)|)

In regex form:

以正则表达式:

/http:\/\/example.com\/foo(?:\/|\/(\w+)|)/

This will match example.com/foo or example.com/foo/bar or example.com/foo/

这将匹配example.com/foo或example.com/foo/bar或example.com/foo/

Some explaination:

(foo|bar) matches foo or bar

(foo | bar)匹配foo或bar

(?:) a group with the ?: in the begin will not been captured

(?:)一个组中的?:在开头不会被捕获

\/ will match a / at the end

\ /将匹配最后一个/

\/(\w+) match a / with a word character who is repeated one or more times

\ /(\ w +)将a /与重复一次或多次的单词字符匹配

|) will match nothing at the end of the string.

|)将匹配字符串末尾的任何内容。

#4

I would use a negative lookahead (?!) for this:

我会使用负向前瞻(?!):

$urls = array(
    'http://example.com/foo',
    'http://example.com/foo/',
    'http://example.com/foo/bar',
    'http://example.com/foobar'
);

foreach ($urls as $url) {
    if (preg_match('#^http://example\.com/foo(?!bar)#', $url)) {
        echo $url, " matches.\n";
    } else {
        echo $url, " does NOT match.\n";
    }
}

// Output:
// http://example.com/foo matches.
// http://example.com/foo/ matches.
// http://example.com/foo/bar matches.
// http://example.com/foobar does NOT match.

#5

Javascript Regular Expression

Javascript正则表达式

https?://(example.com)/?/[^/]*/?(bar)?

Test here:(More Info..)

#1