How can I merge two MySQL tables that have the same structure?
如何合并具有相同结构的两个MySQL表?
The primary keys of the two tables will *, so I have take that into account.
这两个表的主键会发生冲突,所以我已经考虑到了这一点。
6 个解决方案
#1
111
You can also try:
你也可以尝试:
INSERT IGNORE
INTO table_1
SELECT *
FROM table_2
;
which allows those rows in table_1 to supersede those in table_2 that have a matching primary key, while still inserting rows with new primary keys.
它允许table_1中的那些行取代table_2中的那些具有匹配主键的行,同时仍然插入带有新主键的行。
Alternatively,
另外,
REPLACE
INTO table_1
SELECT *
FROM table_2
;
will update those rows already in table_1 with the corresponding row from table_2, while inserting rows with new primary keys.
将使用表_2中的对应行更新表_1中已经存在的行,同时使用新的主键插入行。
#2
36
It depends on the semantic of the primary key. If it's just autoincrement, then use something like:
这取决于主键的语义。如果它只是自动递增的,那么使用如下内容:
insert into table1 (all columns except pk)
select all_columns_except_pk
from table2;
If PK means something, you need to find a way to determine which record should have priority. You could create a select query to find duplicates first (see answer by cpitis). Then eliminate the ones you don't want to keep and use the above insert to add records that remain.
如果PK意味着什么,您需要找到一种方法来确定哪个记录应该具有优先级。您可以创建一个select查询,以首先查找重复的内容(参见cpitis的answer)。然后删除那些您不想保存的,并使用上面的insert来添加剩下的记录。
#3
20
INSERT
INTO first_table f
SELECT *
FROM second_table s
ON DUPLICATE KEY
UPDATE
s.column1 = DO_WHAT_EVER_MUST_BE_DONE_ON_KEY_*(f.column1)
#4
14
If you need to do it manually, one time:
如果需要手工操作,一次:
First, merge in a temporary table, with something like:
首先,合并到临时表中,合并如下内容:
create table MERGED as select * from table 1 UNION select * from table 2
Then, identify the primary key constraints with something like
然后,用类似的方法确定主键约束。
SELECT COUNT(*), PK from MERGED GROUP BY PK HAVING COUNT(*) > 1
Where PK is the primary key field...
其中PK是主键字段…
Solve the duplicates.
解决重复。
Rename the table.
重命名表。
[edited - removed brackets in the UNION query, which was causing the error in the comment below]
[已编辑-在UNION查询中删除括号,导致下面注释中的错误]
#5
6
Not as complicated as it sounds.... Just leave the duplicate primary key out of your query.... this works for me !
不像听起来那么复杂....只是离开的重复的主键查询....这对我很有效!
INSERT INTO
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`status`,
content_category,
content_type,
content_id,
user_id,
title,
description,
content_file,
content_url,
tags,
create_date,
edit_date,
runs
)
SELECT `status`,
content_category,
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edit_date,
runs
FROM
Content_Images
#6
0
You could write a script to update the FK's for you.. check out this blog: http://multunus.com/2011/03/how-to-easily-merge-two-identical-mysql-databases/
你可以写一个脚本为你更新FK。看看这个博客:http://multunus.com/2011/03/how- easy -merge-two-同一性-mysql-databases/
They have a clever script to use the information_schema tables to get the "id" columns:
他们有一个聪明的脚本,使用information_schema表获取“id”列:
SET @db:='id_new';
select @max_id:=max(AUTO_INCREMENT) from information_schema.tables;
select concat('update ',table_name,' set ', column_name,' = ',column_name,'+',@max_id,' ; ') from information_schema.columns where table_schema=@db and column_name like '%id' into outfile 'update_ids.sql';
use id_new
source update_ids.sql;
#1
111
You can also try:
你也可以尝试:
INSERT IGNORE
INTO table_1
SELECT *
FROM table_2
;
which allows those rows in table_1 to supersede those in table_2 that have a matching primary key, while still inserting rows with new primary keys.
它允许table_1中的那些行取代table_2中的那些具有匹配主键的行,同时仍然插入带有新主键的行。
Alternatively,
另外,
REPLACE
INTO table_1
SELECT *
FROM table_2
;
will update those rows already in table_1 with the corresponding row from table_2, while inserting rows with new primary keys.
将使用表_2中的对应行更新表_1中已经存在的行,同时使用新的主键插入行。
#2
36
It depends on the semantic of the primary key. If it's just autoincrement, then use something like:
这取决于主键的语义。如果它只是自动递增的,那么使用如下内容:
insert into table1 (all columns except pk)
select all_columns_except_pk
from table2;
If PK means something, you need to find a way to determine which record should have priority. You could create a select query to find duplicates first (see answer by cpitis). Then eliminate the ones you don't want to keep and use the above insert to add records that remain.
如果PK意味着什么,您需要找到一种方法来确定哪个记录应该具有优先级。您可以创建一个select查询,以首先查找重复的内容(参见cpitis的answer)。然后删除那些您不想保存的,并使用上面的insert来添加剩下的记录。
#3
20
INSERT
INTO first_table f
SELECT *
FROM second_table s
ON DUPLICATE KEY
UPDATE
s.column1 = DO_WHAT_EVER_MUST_BE_DONE_ON_KEY_*(f.column1)
#4
14
If you need to do it manually, one time:
如果需要手工操作,一次:
First, merge in a temporary table, with something like:
首先,合并到临时表中,合并如下内容:
create table MERGED as select * from table 1 UNION select * from table 2
Then, identify the primary key constraints with something like
然后,用类似的方法确定主键约束。
SELECT COUNT(*), PK from MERGED GROUP BY PK HAVING COUNT(*) > 1
Where PK is the primary key field...
其中PK是主键字段…
Solve the duplicates.
解决重复。
Rename the table.
重命名表。
[edited - removed brackets in the UNION query, which was causing the error in the comment below]
[已编辑-在UNION查询中删除括号,导致下面注释中的错误]
#5
6
Not as complicated as it sounds.... Just leave the duplicate primary key out of your query.... this works for me !
不像听起来那么复杂....只是离开的重复的主键查询....这对我很有效!
INSERT INTO
Content(
`status`,
content_category,
content_type,
content_id,
user_id,
title,
description,
content_file,
content_url,
tags,
create_date,
edit_date,
runs
)
SELECT `status`,
content_category,
content_type,
content_id,
user_id,
title,
description,
content_file,
content_url,
tags,
create_date,
edit_date,
runs
FROM
Content_Images
#6
0
You could write a script to update the FK's for you.. check out this blog: http://multunus.com/2011/03/how-to-easily-merge-two-identical-mysql-databases/
你可以写一个脚本为你更新FK。看看这个博客:http://multunus.com/2011/03/how- easy -merge-two-同一性-mysql-databases/
They have a clever script to use the information_schema tables to get the "id" columns:
他们有一个聪明的脚本,使用information_schema表获取“id”列:
SET @db:='id_new';
select @max_id:=max(AUTO_INCREMENT) from information_schema.tables;
select concat('update ',table_name,' set ', column_name,' = ',column_name,'+',@max_id,' ; ') from information_schema.columns where table_schema=@db and column_name like '%id' into outfile 'update_ids.sql';
use id_new
source update_ids.sql;