I would like to calculate the exact hours difference between two datetime variables. The hours difference should be exact like this:
我想计算两个日期时间变量之间的确切小时差。小时差异应该是这样的:
1.5
2
6.25
Anybody please help out..Thanks in advance...
有人请帮忙..谢谢你...
5 个解决方案
#1
21
You could use DATEDIFF
to find the difference in minutes and convert that into hours:
您可以使用DATEDIFF查找分钟差异并将其转换为小时:
select datediff(mi, startdate, enddate)
Assuming 1.5 means 1 hour and 30 minutes you could simply divide the result by 60:
假设1.5表示1小时30分钟,您可以简单地将结果除以60:
select datediff(mi, startdate, enddate) / 60.0
#2
3
it will help you....
它会帮助你......
Declare @Date1 dateTime
Declare @Date2 dateTime
Set @Date1 = '22:30:00'
Set @Date2 = '00:00:00'
Select Cast((@Date1 - @Date2) as Float) * 24.0
#3
3
Keep it simple, son.
保持简单,儿子。
declare @date1 datetime
declare @date2 datetime
select @date1 = GETDATE();
select @date2 = '2013-02-02 14:05'
select DATEDIFF(hh, @date2, @date1)
Results
-----------
71
(1 row(s) affected)
#4
1
Please try:
declare @dt1 datetime, @dt2 datetime, @Seconds int
select @dt1='2013-02-05 14:05:55.113', @dt2 =getdate()
set @Seconds=datediff(second, @dt1, @dt2)
declare @Hour nvarchar(50)
declare @Min nvarchar(50)
declare @MinTemp int
if @Seconds >0
begin
set @Hour=cast((@Seconds / 3600) as nvarchar(20)) +' Hrs '
set @MinTemp= (@Seconds % 3600) / 60
set @Min=cast(@MinTemp as nvarchar(20))
if @MinTemp<10
select @Hour+'0'+@Min +' Min'
else
select @Hour+@Min +' Min'
end
else
select '00 Hrs 00 Min'
#5
0
To get Exact Time Difference in HH:MM try the below code in MS-SQL
要在HH中获得精确时间差:MM在MS-SQL中尝试以下代码
Declare @InTime datetime='2017-11-27 10:00:00',
@OutTime datetime='2017-11-27 11:15:00'
SELECT CONVERT(varchar(5),DATEADD(minute,DATEDIFF(minute,@InTime,@OutTime),0), 114)
-----------
Result
01:15
#1
21
You could use DATEDIFF
to find the difference in minutes and convert that into hours:
您可以使用DATEDIFF查找分钟差异并将其转换为小时:
select datediff(mi, startdate, enddate)
Assuming 1.5 means 1 hour and 30 minutes you could simply divide the result by 60:
假设1.5表示1小时30分钟,您可以简单地将结果除以60:
select datediff(mi, startdate, enddate) / 60.0
#2
3
it will help you....
它会帮助你......
Declare @Date1 dateTime
Declare @Date2 dateTime
Set @Date1 = '22:30:00'
Set @Date2 = '00:00:00'
Select Cast((@Date1 - @Date2) as Float) * 24.0
#3
3
Keep it simple, son.
保持简单,儿子。
declare @date1 datetime
declare @date2 datetime
select @date1 = GETDATE();
select @date2 = '2013-02-02 14:05'
select DATEDIFF(hh, @date2, @date1)
Results
-----------
71
(1 row(s) affected)
#4
1
Please try:
declare @dt1 datetime, @dt2 datetime, @Seconds int
select @dt1='2013-02-05 14:05:55.113', @dt2 =getdate()
set @Seconds=datediff(second, @dt1, @dt2)
declare @Hour nvarchar(50)
declare @Min nvarchar(50)
declare @MinTemp int
if @Seconds >0
begin
set @Hour=cast((@Seconds / 3600) as nvarchar(20)) +' Hrs '
set @MinTemp= (@Seconds % 3600) / 60
set @Min=cast(@MinTemp as nvarchar(20))
if @MinTemp<10
select @Hour+'0'+@Min +' Min'
else
select @Hour+@Min +' Min'
end
else
select '00 Hrs 00 Min'
#5
0
To get Exact Time Difference in HH:MM try the below code in MS-SQL
要在HH中获得精确时间差:MM在MS-SQL中尝试以下代码
Declare @InTime datetime='2017-11-27 10:00:00',
@OutTime datetime='2017-11-27 11:15:00'
SELECT CONVERT(varchar(5),DATEADD(minute,DATEDIFF(minute,@InTime,@OutTime),0), 114)
-----------
Result
01:15