为什么strptime是4小时休息？

How do I use strptime to format "%Y-%m-%dT%H:%M:%SZ" into the correct UNIX timestamp?

如何使用strptime将“%Y-%m-%dT%H:%M:%SZ”格式化为正确的UNIX时间戳?

I tried writing a method called testDateWithString (below).

我尝试编写一个名为testDateWithString的方法(下面)。

But, it fails with error message:

但是,它失败并显示错误消息:

'2011-12-27 08:35:46 +0000' should be equal to '2011-12-27 04:35:46 +0000'

'2011-12-27 08:35:46 +0000'应该等于'2011-12-27 04:35:46 +0000'

How can I fix this?

我怎样才能解决这个问题?

#import <SenTestingKit/SenTestingKit.h>

@implementation NSDate (DateWithString)

+ (id)dateWithString:(NSString *)string {
    struct tm time; strptime([string UTF8String], "%Y-%m-%dT%H:%M:%SZ", &time);
    return [NSDate dateWithTimeIntervalSince1970:mktime(&time)];
}

@end

@interface NSDateTests : SenTestCase
@end

@implementation NSDateTests

- (void)testDateWithString {
    NSDate *parsedDate = [NSDate dateWithString:@"2011-12-27T04:35:46Z"];
    NSDate *actualDate = [NSDate dateWithTimeIntervalSince1970:1324960546];
    STAssertEqualObjects(parsedDate, actualDate, nil);
}

@end

1 个解决方案

#1

mktime is giving you local time, not GMT.

mktime给你当地时间,而不是GMT。

Take a look at this answer for more details: Converting Between Local Times and GMT/UTC in C/C++

请查看此答案以获取更多详细信息:在C / C ++中在本地时间和GMT / UTC之间进行转换

#1