I have two tables, keywords and data.
我有两个表,关键字和数据。
Table keywords have 2 columns (id, keyword), table data have 3 columns (id[foreign key of keywords.id], name, value).
表关键字有2列(id,关键字),表数据有3列(id [keywords.id]的外键,名称,值)。
I am using this query:
我正在使用此查询:
SELECT k.id, d.value, d.name
FROM keywords AS k
INNER JOIN data as d ON k.id = d.id
it returns something like:
它返回的内容如下:
1 123 name1
1 456 name2
2 943 name1
3 542 name1
3 532 name2
3 682 name3
Each id can have values from 0 to 3 (maybe more in the future).
每个id可以具有0到3的值(将来可能更多)。
How can I retrieve all the rows with the same id in the same row?
如何在同一行中检索具有相同ID的所有行?
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1 123 456
2 943
3 542 532 682
I want to do this because I want to be able to sort the values.
我想这样做是因为我希望能够对值进行排序。
1 个解决方案
#1
65
Use GROUP_CONCAT()
like this:
像这样使用GROUP_CONCAT():
SELECT k.id, GROUP_CONCAT(d.value)
FROM keywords AS k
INNER JOIN data as d ON k.id = d.id
GROUP BY k.id
Also, you may need to do ORDER BY d.name
to get exact order of values as you want. Like this:
此外,您可能需要执行ORDER BY d.name以获得所需的确切值顺序。喜欢这个:
SELECT k.id, GROUP_CONCAT(d.value ORDER BY d.name separator ' ')
FROM keywords AS k
INNER JOIN data as d ON k.id = d.id
GROUP BY k.id
#1
65
Use GROUP_CONCAT()
like this:
像这样使用GROUP_CONCAT():
SELECT k.id, GROUP_CONCAT(d.value)
FROM keywords AS k
INNER JOIN data as d ON k.id = d.id
GROUP BY k.id
Also, you may need to do ORDER BY d.name
to get exact order of values as you want. Like this:
此外,您可能需要执行ORDER BY d.name以获得所需的确切值顺序。喜欢这个:
SELECT k.id, GROUP_CONCAT(d.value ORDER BY d.name separator ' ')
FROM keywords AS k
INNER JOIN data as d ON k.id = d.id
GROUP BY k.id