如何使用javascript删除json数组中的特定字段？ [重复]

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How to change value of object which is inside an array using JavaScript or jQuery? 13 answers
如何使用JavaScript或jQuery更改数组内的对象的值？ 13个答案

[
  {

    "user_pass": "$PBa5$.cxL91nBU5cG4gqhNp8mWZoJgFY/",
    "user_mobile":"1234567890",
    "user_nicename": "abc",
    "user_email": "abc@gmail.com",
    "user_status": 0

  },
  {

    "user_pass": "$P$BwfQRzajR6R9eLeZbPnTgfQfsfPDhK0",
    "user_mobile":"0987654321",
    "user_nicename": "cdv",
    "user_email": "cdv@gmail.com",
    "user_status": 0
  },
  {

    "user_pass": "$P$Be15Zwqze.9OxoYfTOMd0WjlgXO7xe.",
    "user_mobile":"5432167890",
    "user_nicename": "zxc",
    "user_email": "zxc@gmail.com",
    "user_status": 0
  }
 ]

Above is my data.

以上是我的数据。

1 . I want to delete user_pass field in every object.

1。我想删除每个对象中的user_pass字段。

2 . I want to use user_mobile as user_pass

2。我想将user_mobile用作user_pass

my expectation result:

我的期望结果：

below i have mentioned my final result

下面我提到了我的最终结果

[
  {

    "user_pass": "1234567890",
    "user_mobile":"1234567890",
    "user_nicename": "abc",
    "user_email": "abc@gmail.com",
    "user_status": 0

  },
  {

    "user_pass": "0987654321",
    "user_mobile":"0987654321",
    "user_nicename": "cdv",
    "user_email": "cdv@gmail.com",
    "user_status": 0
  },
  {

    "user_pass": "5432167890",
    "user_mobile":"5432167890",
    "user_nicename": "zxc",
    "user_email": "zxc@gmail.com",
    "user_status": 0
  }
 ]

any one help me out i am new to this technology .

任何人帮助我，我是这项技术的新手。

6 个解决方案

#1

You have to loop through the object array and reference user_mobile to user_pass.

您必须遍历对象数组并将user_mobile引用到user_pass。

var arr = [...data...];

arr.forEach(function(obj) {
    obj.user_pass = obj.user_mobile;
});

#2

forEach

的forEach

var arr=[ { "user_pass": "$PBa5$.cxL91nBU5cG4gqhNp8mWZoJgFY/", "user_mobile":"1234567890", "user_nicename": "abc", "user_email": "abc@gmail.com", "user_status": 0 }, { "user_pass": "$P$BwfQRzajR6R9eLeZbPnTgfQfsfPDhK0", "user_mobile":"0987654321", "user_nicename": "cdv", "user_email": "cdv@gmail.com", "user_status": 0 }, { "user_pass": "$P$Be15Zwqze.9OxoYfTOMd0WjlgXO7xe.", "user_mobile":"5432167890", "user_nicename": "zxc", "user_email": "zxc@gmail.com", "user_status": 0 } ];
arr.forEach(function(a){
a.user_pass=a.user_mobile;
})
console.log(arr);

#3

var data = [{

  "user_pass": "$PBa5$.cxL91nBU5cG4gqhNp8mWZoJgFY/",
  "user_mobile": "1234567890",
  "user_nicename": "abc",
  "user_email": "abc@gmail.com",
  "user_status": 0

}, {

  "user_pass": "$P$BwfQRzajR6R9eLeZbPnTgfQfsfPDhK0",
  "user_mobile": "0987654321",
  "user_nicename": "cdv",
  "user_email": "cdv@gmail.com",
  "user_status": 0
}, {

  "user_pass": "$P$Be15Zwqze.9OxoYfTOMd0WjlgXO7xe.",
  "user_mobile": "5432167890",
  "user_nicename": "zxc",
  "user_email": "zxc@gmail.com",
  "user_status": 0
}];

var newData = data.map(function(item) {
  return {
    user_pass: item.user_mobile,
    user_mobile: item.user_mobile,
    user_nicename: item.user_nicename,
    user_email: item.user_email,
    user_status: item.user_status
  };
});

console.log(newData);

#4

If you need to do it in an immutable way you could map over the array and Assign all the object properties to new objects.

如果需要以不可变的方式执行此操作，则可以映射数组并将所有对象属性分配给新对象。

const data = [
  {

    "user_pass": "$PBa5$.cxL91nBU5cG4gqhNp8mWZoJgFY/",
    "user_mobile":"1234567890",
    "user_nicename": "abc",
    "user_email": "abc@gmail.com",
    "user_status": 0

  },
  {

    "user_pass": "$P$BwfQRzajR6R9eLeZbPnTgfQfsfPDhK0",
    "user_mobile":"0987654321",
    "user_nicename": "cdv",
    "user_email": "cdv@gmail.com",
    "user_status": 0
  },
  {

    "user_pass": "$P$Be15Zwqze.9OxoYfTOMd0WjlgXO7xe.",
    "user_mobile":"5432167890",
    "user_nicename": "zxc",
    "user_email": "zxc@gmail.com",
    "user_status": 0
  }
 ]

const newData = data.map(user => 
  Object.assign({}, user, {
    user_pass: user.user_mobile
  }))

console.log(data)
console.log(newData)
console.log(data === newData)
console.log(data[0] === newData[0])

<script src="http://codepen.io/synthet1c/pen/WrQapG.js"></script>

#5

for (var i in users) { users[i].user_pass= users[i].user_mobile; }

#6

-1

Here you go

干得好

var obj = [
  {

    "user_pass": "$PBa5$.cxL91nBU5cG4gqhNp8mWZoJgFY/",
    "user_mobile":"1234567890",
    "user_nicename": "abc",
    "user_email": "abc@gmail.com",
    "user_status": 0

  },
  {

    "user_pass": "$P$BwfQRzajR6R9eLeZbPnTgfQfsfPDhK0",
    "user_mobile":"0987654321",
    "user_nicename": "cdv",
    "user_email": "cdv@gmail.com",
    "user_status": 0
  },
  {

    "user_pass": "$P$Be15Zwqze.9OxoYfTOMd0WjlgXO7xe.",
    "user_mobile":"5432167890",
    "user_nicename": "zxc",
    "user_email": "zxc@gmail.com",
    "user_status": 0
  }
 ]

for(var i =0 ; i < obj.length; i++){
     obj[i].user_pass= obj[i].user_mobile
}

console.log(obj);

#1