多值获取参数——路由生成

When using multi-value GET parameters like so:

当使用多值时，得到如下参数:

/?param=1&param=2&param=3

You can automatically model-bind to a list, like so:

您可以自动将模型绑定到列表，如下所示:

public ActionResult MyAction(List<int> param)

How can I pass such values using anonymous types, in URL generation?

如何在URL生成中使用匿名类型传递这些值?

@Url.Action("MyAction", new { param = ?? })

Using an array / list doesn't work -

使用数组/列表不工作-

@Url.Action("MyAction", new { param = new List<string>{ "1", "2", "3" } })

As it just spits out Object.ToString() like:

因为它刚刚吐出Object.ToString() like:

?param=System.Collections.Generic.List%601%5BSystem.String%5D

Cheers

干杯

1 个解决方案

#1

Not the nice solution your after, buy you could do, assuming you know whether to add the ? or not.

如果你知道是否要添加的话，买你能做的，不是一个好的解决方案。与否。

@Url.Action("MyAction")?param=@string.Join("&param=", new [] {1, 2, 3})

Maybe a helper could be written that does this. see URL.Action with a string array?

也许可以写一个助手来做这个。看到URL。使用字符串数组操作?