@author: ZZQ
@software: PyCharm
@file: mergeTwoLists.py
@time: 2018/9/16 20:49
要求:将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
e.g.:
输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4
# Definition for singly-linked list.
class ListNode(object):
def __init__(self, x):
self.val = x
self.next = None
class Solution():
def __init__(self):
pass
def mergeTwoLists(self, l1, l2):
"""
:type l1: ListNode
:type l2: ListNode
:rtype: ListNode
"""
if l1 is None and l2 is None:
return None
if l1 is None:
return l2
if l2 is None:
return l1
l3 = ListNode(0)
head = l3
while l1 is not None and l2 is not None:
if l1.val > l2.val:
head.next = l2
l2 = l2.next
else:
head.next = l1
l1 = l1.next
head = head.next
if l1 is not None and l2 is None:
head.next = l1
if l1 is None and l2 is not None:
head.next = l2
return head.next