获取url中？后面传递的参数

function  getUrlArgs(){
            var url=location.href;
            var i=url.indexOf('?');
            if(i==-1)return;
            var querystr=url.substr(i+1);
            var arr1=querystr.split('&');
            var arr2=new Object();
            for (i in arr1){
                var t=arr1[i].split('=');
                arr2[t[0]]=t[1];
            }
            return arr2;
}