如何在ASP.NET MVC中获取模型的HtmlHelper 实例?

时间:2021-12-20 04:14:06

Let's say I have an Index view. The model I pass in is actually a collection of models, so the Html property is of type HtmlHelper<List<MyModel>>. If I want to call extension methods (e.g., Display() or DisplayFor() on the individual items in the list, however, I think I need to obtain an HtmlHelper<MyModel>. But how?

假设我有一个索引视图。我传入的模型实际上是模型的集合,因此Html属性的类型为HtmlHelper >。如果我想在列表中的各个项目上调用扩展方法(例如,Display()或DisplayFor(),我想我需要获取HtmlHelper 。但是如何?

I tried using the HtmlHelper<TModel> constructor, which looks like this:

我尝试使用HtmlHelper 构造函数,如下所示:

HtmlHelper<TModel>(ViewContext, IViewDataContainer)

But I'm not having any luck with that. I don't know how to obtain the IViewDataContainer for the item, and the documentation on these things is very sparse.

但我没有运气。我不知道如何为该项获取IViewDataContainer,并且关于这些东西的文档非常稀疏。

A lot of magic apparently happens when I do...

当我这么做时,显然会发生很多魔法......

return View(List<MyModel>);

...in my controller.

......在我的控制器里

How do I recreate that magic on individual items in a list/collection?

如何在列表/集合中的单个项目上重新创建魔法?

Update

Here is a code snippet to show what I'm trying to accomplish:

这是一个代码片段,显示我正在尝试完成的任务:

        foreach(var item in items)
        {
            var helper = new HtmlHelper<ProjName.MyModel>(ViewContext, ????);
%>
            <tr>
<%
                foreach(var property in properties)
                {
%>
                    <td>
                        <%=  helper.Display(property.DisplayName) %>
                    </td>
<%          
                }
%>
            </tr>
<%
        }

Basically, I want to populate the cells of a table using the items in the collection. I just need help setting the helper variable.

基本上,我想使用集合中的项目填充表格的单元格。我只需要帮助设置辅助变量。

3 个解决方案

#1


2  

One idea is to use RenderPartial. So create a user control which has the type of your model (MyModel). Then in your main view, add the following code.

一个想法是使用RenderPartial。因此,创建一个具有模型类型(MyModel)的用户控件。然后在主视图中,添加以下代码。

<% Html.RenderPartial("SubView", property); %>

So the main view would look like:

所以主视图看起来像:

 foreach(var item in items) 
 { 
    %> 
    <tr> 
    <% 
        foreach(var property in properties) 
        { 
         %> 
            <td> 
                <%= Html.RenderPartial("SubView", property) %> 
            </td> 
        <%           
        } 
        %> 
    </tr> 
    <% 
    }
    %>

Then the sub view would be a strongly typed user control of type . The sub view can then just call the helper and it will be of the correct type:

然后子视图将是类型的强类型用户控件。然后子视图可以只调用帮助程序,它将是正确的类型:

<%= Html.Display(Model.DisplayName) %>

#2


1  

Phil Haack to the rescue!

菲尔哈克救援!

http://haacked.com/archive/2010/05/05/asp-net-mvc-tabular-display-template.aspx

#3


0  

The page itself is a IViewDataContainer. You could try that :

页面本身是一个IViewDataContainer。你可以尝试:

foreach(MyModel m in Model)
{
    HtmlHelper helper = new HtmlHelper<MyModel>(ViewContext, this);
    ...
}

UPDATE

Another idea : you could create a ViewUserControl<MyModel> and use RenderPartial to render each item with this control. ViewUserControl<MyModel> exposes a HtmlHelper<MyModel> that you can use to render the model

另一个想法是:您可以创建一个ViewUserControl 并使用RenderPartial来渲染具有此控件的每个项目。 ViewUserControl 公开可用于呈现模型的HtmlHelper

#1


2  

One idea is to use RenderPartial. So create a user control which has the type of your model (MyModel). Then in your main view, add the following code.

一个想法是使用RenderPartial。因此,创建一个具有模型类型(MyModel)的用户控件。然后在主视图中,添加以下代码。

<% Html.RenderPartial("SubView", property); %>

So the main view would look like:

所以主视图看起来像:

 foreach(var item in items) 
 { 
    %> 
    <tr> 
    <% 
        foreach(var property in properties) 
        { 
         %> 
            <td> 
                <%= Html.RenderPartial("SubView", property) %> 
            </td> 
        <%           
        } 
        %> 
    </tr> 
    <% 
    }
    %>

Then the sub view would be a strongly typed user control of type . The sub view can then just call the helper and it will be of the correct type:

然后子视图将是类型的强类型用户控件。然后子视图可以只调用帮助程序,它将是正确的类型:

<%= Html.Display(Model.DisplayName) %>

#2


1  

Phil Haack to the rescue!

菲尔哈克救援!

http://haacked.com/archive/2010/05/05/asp-net-mvc-tabular-display-template.aspx

#3


0  

The page itself is a IViewDataContainer. You could try that :

页面本身是一个IViewDataContainer。你可以尝试:

foreach(MyModel m in Model)
{
    HtmlHelper helper = new HtmlHelper<MyModel>(ViewContext, this);
    ...
}

UPDATE

Another idea : you could create a ViewUserControl<MyModel> and use RenderPartial to render each item with this control. ViewUserControl<MyModel> exposes a HtmlHelper<MyModel> that you can use to render the model

另一个想法是:您可以创建一个ViewUserControl 并使用RenderPartial来渲染具有此控件的每个项目。 ViewUserControl 公开可用于呈现模型的HtmlHelper