I have the following table:
我有下表:
+----+-----------+-----+
| p1 | p2 | model| res |
+----+-----------+-----+
| 1 | a | dog | 1 |
| 2 | a | dog | 2 |
| 1 | b | dog | 3 |
| 2 | b | dog | 4 |
| 1 | a | cat | 10 |
| 2 | a | cat | 2 |
| 1 | b | cat | 10 |
| 2 | b | cat | 1 |
+----+-----------+-----+
What I want, is for each combination of p1 and p2, select the one that gets the lowest sum for res over for all models). The sum scores in this case are:
我想要的是,对于p1和p2的每一个组合,选择一个在所有模型中得到最小值的值。本例的总分为:
p1=1, p2=a: 1+10=11
p1=2, p2=a: 2+2=4
p1=1, p2=b: 3+10=13
p1=2, p2=b: 4+1=5
So I would like to get the following table:
所以我想要下表:
+----+-----------+-----+
| p1 | p2 | model| res |
+----+-----------+-----+
| 2 | a | dog | 2 |
| 2 | a | cat | 2 |
+----+-----------+-----+
Note: There may be more p columns (i.e p3, p4,...)
注意:可能有更多的p列(i)。e p3,p4,…)
What sql select query should I use in order to get the desired table above?
为了得到所需的表,我应该使用什么sql select查询?
2 个解决方案
#1
2
http://sqlfiddle.com/#!7/af26b/5
http://sqlfiddle.com/ ! 7 / af26b / 5
SELECT t1.*
FROM TEST t1
JOIN (
SELECT p1, p2
FROM TEST
GROUP BY p1, p2
ORDER BY SUM(res)
LIMIT 1) t2 ON t1.p1 = t2.p1 AND t1.p2 = t2.p2
#2
0
Would something like this help?
有这样的帮助吗?
select * from the_table
group by model # do it for each distinct model
order by res ascending # to get the lower ones first so that limit can pick them
limit 1 # for each group, i think it will do that.
#1
2
http://sqlfiddle.com/#!7/af26b/5
http://sqlfiddle.com/ ! 7 / af26b / 5
SELECT t1.*
FROM TEST t1
JOIN (
SELECT p1, p2
FROM TEST
GROUP BY p1, p2
ORDER BY SUM(res)
LIMIT 1) t2 ON t1.p1 = t2.p1 AND t1.p2 = t2.p2
#2
0
Would something like this help?
有这样的帮助吗?
select * from the_table
group by model # do it for each distinct model
order by res ascending # to get the lower ones first so that limit can pick them
limit 1 # for each group, i think it will do that.