将秒值转换为小时分钟秒？

I've been trying to convert a value of seconds (in a BigDecimal variable) to a string in an editText like "1 hour 22 minutes 33 seconds" or something of the kind.

我一直在尝试将秒值（在BigDecimal变量中）转换为editText中的字符串，如“1小时22分33秒”或类似的东西。

I've tried this:

我试过这个：

String sequenceCaptureTime = "";
BigDecimal roundThreeCalc = new BigDecimal("0");
BigDecimal hours = new BigDecimal("0");
BigDecimal myremainder = new BigDecimal("0");
BigDecimal minutes = new BigDecimal("0");
BigDecimal seconds = new BigDecimal("0");
BigDecimal var3600 = new BigDecimal("3600");
BigDecimal var60 = new BigDecimal("60");

(I have a roundThreeCalc which is the value in seconds so I try to convert it here.)

（我有一个roundThreeCalc，这是秒的值，所以我尝试在这里转换它。）

hours = (roundThreeCalc.divide(var3600));
myremainder = (roundThreeCalc.remainder(var3600));
minutes = (myremainder.divide(var60));
seconds = (myremainder.remainder(var60));
sequenceCaptureTime =  hours.toString() + minutes.toString() + seconds.toString();

Then I set the editText to sequnceCaptureTime String. But that didn't work. It force closed the app every time. I am totally out of my depth here, any help is greatly appreciated. Happy coding!

然后我将editText设置为sequnceCaptureTime String。但那没用。它每次强制关闭应用程序。我完全不在这里，任何帮助都非常感谢。快乐的编码！

17 个解决方案

#1

You should have more luck with

你应该有更多的运气

hours = roundThreeCalc.divide(var3600, BigDecimal.ROUND_FLOOR);
myremainder = roundThreeCalc.remainder(var3600);
minutes = myremainder.divide(var60, BigDecimal.ROUND_FLOOR);
seconds = myremainder.remainder(var60);

This will drop the decimal values after each division.

这将在每次除法后删除小数值。

Edit: If that didn't work, try this. (I just wrote and tested it)

编辑：如果这不起作用，试试这个。 （我刚刚编写并测试过它）

public static int[] splitToComponentTimes(BigDecimal biggy)
{
    long longVal = biggy.longValue();
    int hours = (int) longVal / 3600;
    int remainder = (int) longVal - hours * 3600;
    int mins = remainder / 60;
    remainder = remainder - mins * 60;
    int secs = remainder;

    int[] ints = {hours , mins , secs};
    return ints;
}

#2

Is it necessary to use a BigDecimal? If you don't have to, I'd use an int or long for seconds, and it would simplify things a little bit:

是否有必要使用BigDecimal？如果你没有，我会使用int或long for seconds，它会简化一些事情：

hours = totalSecs / 3600;
minutes = (totalSecs % 3600) / 60;
seconds = totalSecs % 60;

timeString = String.format("%02d:%02d:%02d", hours, minutes, seconds);

You might want to pad each to make sure they're two digit values(or whatever) in the string, though.

您可能想要填充每个以确保它们是字符串中的两位数值（或其他）。

#3

DateUtils.formatElapsedTime(long), formats an elapsed time in the form "MM:SS" or "H:MM:SS" . It returns the String you are looking for. You can find the documentation here

DateUtils.formatElapsedTime（long），以“MM：SS”或“H：MM：SS”的形式格式化经过的时间。它返回您要查找的String。你可以在这里找到文档

#4

Here is the working code:

这是工作代码：

private String getDurationString(int seconds) {

    int hours = seconds / 3600;
    int minutes = (seconds % 3600) / 60;
    seconds = seconds % 60;

    return twoDigitString(hours) + " : " + twoDigitString(minutes) + " : " + twoDigitString(seconds);
}

private String twoDigitString(int number) {

    if (number == 0) {
        return "00";
    }

    if (number / 10 == 0) {
        return "0" + number;
    }

    return String.valueOf(number);
}

#5

Something really helpful in Java 8

import java.time.LocalTime;

private String ConvertSecondToHHMMSSString(int nSecondTime) {
    return LocalTime.MIN.plusSeconds(nSecondTime).toString();
}

#6

private String ConvertSecondToHHMMString(int secondtTime)
{
  TimeZone tz = TimeZone.getTimeZone("UTC");
  SimpleDateFormat df = new SimpleDateFormat("HH:mm:ss");
  df.setTimeZone(tz);
  String time = df.format(new Date(secondtTime*1000L));

  return time;

}

#7

I prefer java's built in TimeUnit library

我更喜欢java内置的TimeUnit库

long seconds = TimeUnit.MINUTES.toSeconds(8);

#8

This is my simple solution:

这是我的简单解决方案：

String secToTime(int sec) {
    int seconds = sec % 60;
    int minutes = sec / 60;
    if (minutes >= 60) {
        int hours = minutes / 60;
        minutes %= 60;
        if( hours >= 24) {
            int days = hours / 24;
            return String.format("%d days %02d:%02d:%02d", days,hours%24, minutes, seconds);
        }
        return String.format("%02d:%02d:%02d", hours, minutes, seconds);
    }
    return String.format("00:%02d:%02d", minutes, seconds);
}

Test Results:

检测结果：

Result: 00:00:36 - 36
Result: 01:00:07 - 3607
Result: 6313 days 12:39:05 - 545488745

#9

Here's my function to address the problem:

这是我解决问题的功能：

public static String getConvertedTime(double time){

    double h,m,s,mil;

    mil = time % 1000;
    s = time/1000;
    m = s/60;
    h = m/60;
    s = s % 60;
    m = m % 60;
    h = h % 24;

    return ((int)h < 10 ? "0"+String.valueOf((int)h) : String.valueOf((int)h))+":"+((int)m < 10 ? "0"+String.valueOf((int)m) : String.valueOf((int)m))
            +":"+((int)s < 10 ? "0"+String.valueOf((int)s) : String.valueOf((int)s))
            +":"+((int)mil > 100 ? String.valueOf((int)mil) : (int)mil > 9 ? "0"+String.valueOf((int)mil) : "00"+String.valueOf((int)mil));
}

#10

I use this:

我用这个：

 public String SEG2HOR( long lnValue) {     //OK
        String lcStr = "00:00:00";
        String lcSign = (lnValue>=0 ? " " : "-");
        lnValue = lnValue * (lnValue>=0 ? 1 : -1); 

        if (lnValue>0) {                
            long lnHor  = (lnValue/3600);
            long lnHor1 = (lnValue % 3600);
            long lnMin  = (lnHor1/60);
            long lnSec  = (lnHor1 % 60);            

                        lcStr = lcSign + ( lnHor < 10 ? "0": "") + String.valueOf(lnHor) +":"+
                              ( lnMin < 10 ? "0": "") + String.valueOf(lnMin) +":"+
                              ( lnSec < 10 ? "0": "") + String.valueOf(lnSec) ;
        }

        return lcStr;           
    }

#11

I like to keep things simple therefore:

因此，我喜欢简单易懂：

    int tot_seconds = 5000;
    int hours = tot_seconds / 3600;
    int minutes = (tot_seconds % 3600) / 60;
    int seconds = tot_seconds % 60;

    String timeString = String.format("%02d Hour %02d Minutes %02d Seconds ", hours, minutes, seconds);

    System.out.println(timeString);

The result will be: 01 Hour 23 Minutes 20 Seconds

结果将是：01小时23分20秒

#12

I know this is pretty old but in java 8:

我知道这很老了但是在java 8中：

LocalTime.MIN.plusSeconds(120).format(DateTimeFormatter.ISO_LOCAL_TIME)

#13

This Code Is working Fine :

本规范工作正常：

txtTimer.setText(String.format("%02d:%02d:%02d",(SecondsCounter/3600), ((SecondsCounter % 3600)/60), (SecondsCounter % 60)));

#14

A nice and easy way to do it using GregorianCalendar

使用GregorianCalendar这是一个很好而简单的方法

Import these into the project:

将这些导入项目：

import java.util.GregorianCalendar;
import java.util.Date;
import java.text.SimpleDateFormat;
import java.util.Scanner;

And then:

接着：

Scanner s = new Scanner(System.in);

System.out.println("Seconds: ");
int secs = s.nextInt();

GregorianCalendar cal = new GregorianCalendar(0,0,0,0,0,secs);
Date dNow = cal.getTime();
SimpleDateFormat ft = new SimpleDateFormat("HH 'hours' mm 'minutes' ss 'seconds'");
System.out.println("Your time: " + ft.format(dNow));

#15

If you want the units h, min and sec for a duration you can use this:

如果你想要持续一段时间的单位h，min和sec，你可以使用：

String convertSeconds(int seconds)
    int h = seconds/ 3600;
    int m = (seconds % 3600) / 60;
    int s = seconds % 60;
    String sh = (h > 0 ? String.valueOf(h) + " " + "h" : "");
    String sm = (m < 10 && m > 0 && h > 0 ? "0" : "") + (m > 0 ? (h > 0 && s == 0 ? String.valueOf(m) : String.valueOf(m) + " " + "min") : "");
    String ss = (s == 0 && (h > 0 || m > 0) ? "" : (s < 10 && (h > 0 || m > 0) ? "0" : "") + String.valueOf(s) + " " + "sec");
    return sh + (h > 0 ? " " : "") + sm + (m > 0 ? " " : "") + ss;
}

int seconds = 3661;
String duration = convertSeconds(seconds);

That's a lot of conditional operators. The method will return those strings:

这是很多条件运算符。该方法将返回这些字符串：

0    -> 0 sec
5    -> 5 sec
60   -> 1 min
65   -> 1 min 05 sec
3600 -> 1 h
3601 -> 1 h 01 sec
3660 -> 1 h 01
3661 -> 1 h 01 min 01 sec
108000 -> 30 h

#16

I use this in python to convert a float representing seconds to hours, minutes, seconds, and microseconds. It's reasonably elegant and is handy for converting to a datetime type via strptime to convert. It could also be easily extended to longer intervals (weeks, months, etc.) if needed.

我在python中使用它将表示秒的浮点数转换为小时，分钟，秒和微秒。它相当优雅，通过strptime转换为日期时间类型很方便。如果需要，它也可以很容易地扩展到更长的间隔（数周，数月等）。

    def sectohmsus(seconds):
        x = seconds
        hmsus = []
        for i in [3600, 60, 1]:  # seconds in a hour, minute, and second
            hmsus.append(int(x / i))
            x %= i
        hmsus.append(int(round(x * 1000000)))  # microseconds
        return hmsus  # hours, minutes, seconds, microsecond

#17

i have tried the best way and less code but may be it is little bit difficult to understand how i wrote my code but if you good at maths it is so easy

我尝试过最好的方法和更少的代码，但可能有点难以理解我是如何编写代码的，但如果你擅长数学就很容易

import java.util.Scanner;

class hours {

上课时间{

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    double s;


    System.out.println("how many second you have ");
    s =input.nextInt();



     double h=s/3600;
     int h2=(int)h;

     double h_h2=h-h2;
     double m=h_h2*60;
     int m1=(int)m;

     double m_m1=m-m1;
     double m_m1s=m_m1*60;






     System.out.println(h2+" hours:"+m1+" Minutes:"+Math.round(m_m1s)+" seconds");





}

}

}

more over it is accurate !

超过它是准确的！