I need to calculate productivity.
我需要计算生产力。
Productivity = some count/ no of Hrs
I have time in HH:MM
我有时间在HH:MM
For example if I take time 1 hrs 30 minutes
例如,如果我需要时间1小时30分钟
Productivity will be
生产力将是
Productivity = some count / 1.3?
OR
Productivity = some count / 1.5?
2 个解决方案
#1
3
If you have 1 hour and 30 minutes, that is 1.5 hours. You would want to take your calculation as: yourValue / 1.5
to get Productivity in units / Hour
如果你有1小时30分钟,那就是1.5小时。您可能需要将计算结果:yourValue / 1.5以单位/小时为单位获得生产力
You would likely want something like:
你可能会想要这样的东西:
SELECT DATEPART(HOUR, @yourTime) + (DATEPART(MINUTE, @yourTime) / 60.) AS pHours;
or more fully something like this, where @Time
is how long the task took:
或更完全类似的东西,其中@Time是任务花了多长时间:
SELECT @workAccomplished /
(DATEPART(HOUR, @Time) + (DATEPART(MINUTE, @Time) / 60.)) AS Productivity;
If you were dividing by 1.3, you would be calculating 1 Hour and 18 minutes, as 0.3 hours = 18 minutes.
如果你除以1.3,你将计算1小时18分钟,0.3小时= 18分钟。
#2
0
declare @workaccomplished int = 240
declare @timeworked int = (SELECT DATEDIFF(hour, '2007-05-07 09:53:01', '2007-05-08 09:53:01'))
--datediff parameters: hour, startingtime , endtime
declare @productivity numeric(8,4) = @workaccomplished / @timeworked
select @productivity
#1
3
If you have 1 hour and 30 minutes, that is 1.5 hours. You would want to take your calculation as: yourValue / 1.5
to get Productivity in units / Hour
如果你有1小时30分钟,那就是1.5小时。您可能需要将计算结果:yourValue / 1.5以单位/小时为单位获得生产力
You would likely want something like:
你可能会想要这样的东西:
SELECT DATEPART(HOUR, @yourTime) + (DATEPART(MINUTE, @yourTime) / 60.) AS pHours;
or more fully something like this, where @Time
is how long the task took:
或更完全类似的东西,其中@Time是任务花了多长时间:
SELECT @workAccomplished /
(DATEPART(HOUR, @Time) + (DATEPART(MINUTE, @Time) / 60.)) AS Productivity;
If you were dividing by 1.3, you would be calculating 1 Hour and 18 minutes, as 0.3 hours = 18 minutes.
如果你除以1.3,你将计算1小时18分钟,0.3小时= 18分钟。
#2
0
declare @workaccomplished int = 240
declare @timeworked int = (SELECT DATEDIFF(hour, '2007-05-07 09:53:01', '2007-05-08 09:53:01'))
--datediff parameters: hour, startingtime , endtime
declare @productivity numeric(8,4) = @workaccomplished / @timeworked
select @productivity