如何使用MongoTemplate将单个字段插入JSON？

So, i am making this program, trying to learn more about Spring and MongoDb. I have built this ticked module, that uses a MongoDb to store ticket info in a JSON format. It looks something like this:

所以,我正在制作这个程序,试图了解有关Spring和MongoDb的更多信息。我已经构建了这个勾选的模块,它使用MongoDb以JSON格式存储票证信息。它看起来像这样:

>  { 
>      "_id" : ObjectId("581fb1a24beb291d27f95a50"),      
>      "userID" : "581ddccb4beb29112a7b4f77", 
>      "ticketStatus" : "Processing", 
>      "ticketSolution" : "Not_Solved",
>      "ticketComment" : null; 
>   }

My question is how do i insert a comment into the "ticketComment" field? (I would need something that uses Criteria.where("ticketID").is(ticketID))

我的问题是如何在“ticketComment”字段中插入注释? (我需要使用Criteria.where(“ticketID”)的东西。是(ticketID))

2 个解决方案

#1

With simplest details use :-

使用最简单的细节: -

Criteria.where("ticketID").is(ticketID));
Query query = new Query(criteria);
BasicDBObject newValues = new BasicDBObject(columnName,value);
BasicDBObject set = new BasicDBObject("$set", newValues);
Update update = new BasicUpdate(set);
mongoOperations.updateMulti(query, update, "collectionName")

#2

So, after some messing around, i have found another approach to this problem.

所以,经过一些麻烦,我找到了解决这个问题的另一种方法。

@Override
public void addTicketComment(String ticketID, String ticketComment) {          
    Ticket ticket = mongoTemplate.findById(ticketID, Ticket.class);
    ticket.getTicketComments().add(ticketComment);
    mongoTemplate.save(ticket);
}

#1