I have a text file having the numbers(of float type) which represents time in seconds. I wish to represent the number of occurances every 15 minutes. The sample of my file is:
我有一个文本文件，其中包含数字（浮点类型），表示以秒为单位的时间。我希望每15分钟代表一次出现次数。我的文件样本是：
0.128766
2.888977
25.087900
102.787657
400.654768
879.090874
903.786754
1367.098789
1456.678567
1786.564569
1909.567567
for first 900 seconds(15 minutes), there are 6 occurances. I want to plot that point on y axis first. Then from 900-1800(next 15 minutes), there are 4 occurances. So, i want to plot 4 on my y-axis next. This should go on...
前900秒（15分钟），有6次出现。我想首先在y轴上绘制该点。然后从900-1800（接下来的15分钟），有4次出现。所以，我想在我的y轴上绘制4。这应该继续......
I know the basic plot() function, but i don't know how to plot every 15 minutes. If there is a link present, please guide me to that link.
我知道基本的plot（）函数，但我不知道如何每15分钟绘制一次。如果有链接，请引导我访问该链接。
2 个解决方案
#1
1
Use findInterval():
使用findInterval（）：
counts <- table(findInterval(x, seq(0, max(x), 900)))
counts
1 2 3
6 4 1
It's easy to plot:
情节很容易：
plot(counts)
#2
0
To build on Andrie's answer. You can add plot(counts, type = 'p') to plot points or plot(counts, type = 'l') to plot a connected line. If you want to plot a curve for the counts you would need to model it using ?lm or ?nls.
以Andrie的答案为基础。您可以将绘图（计数，类型='p'）添加到绘图点或绘图（计数，类型='l'）以绘制连接线。如果要为计数绘制曲线，则需要使用？lm或？nls对其进行建模。
#1
1
Use findInterval():
使用findInterval（）：
counts <- table(findInterval(x, seq(0, max(x), 900)))
counts
1 2 3
6 4 1
It's easy to plot:
情节很容易：
plot(counts)
#2
0
To build on Andrie's answer. You can add plot(counts, type = 'p') to plot points or plot(counts, type = 'l') to plot a connected line. If you want to plot a curve for the counts you would need to model it using ?lm or ?nls.
以Andrie的答案为基础。您可以将绘图（计数，类型='p'）添加到绘图点或绘图（计数，类型='l'）以绘制连接线。如果要为计数绘制曲线，则需要使用？lm或？nls对其进行建模。