无法删除c＃中值之间的某些字符[重复]

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Remove text in-between delimiters in a string (using a regex?) 5 answers
删除字符串中的文本分隔符（使用正则表达式？）5个答案

I am trying to remove characters starting from (and including) rgm up to (and including) ;1..

我试图删除从（包括）rgm到（和包括）的字符; 1 ..

Example input string:

Sum ({rgmdaerudsb;1.Total_Value}, {rgmdaerub;1.Major_Value})

Code:

string strEx = "Sum ({rgmdaerudsb;1.Total_Value}, {rgmdaerub;1.Major_Value})";
strEx = strEx.Substring(0, strEx.LastIndexOf("rgm")) + 
        strEx.Substring(strEx.LastIndexOf(";1.") + 3);

Result:

Sum ({rgmdaerub;1.Total_Value}, {.Major_Value})

Expected result:

Sum ({Total_Value}, {Major_Value})

Note: only rgm and ;1. will remain static and characters between them will vary.

注意：只有rgm和; 1。将保持静态，它们之间的字符会有所不同。

2 个解决方案

#1

I would recommend to use Regex for this purpose. Try this:

我建议将Regex用于此目的。尝试这个：

string input = "Sum ({rgmdaerudsb;1.Total_Value}, {rgmdaerub;1.Major_Value})";
string result = Regex.Replace(input, @"rgm.*?;1\.", "");

Explanation:

说明：

The second parameter of Regex.Replace takes the pattern that consists of the following:

Regex.Replace的第二个参数采用包含以下内容的模式：

rgm (your starting string)
rgm（你的起始字符串）
. (dot - meaning any character)
。（点 - 意思是任何角色）
*? (the preceding symbol can occure zero or more times, but stops at the first possible match (shortest))
*？（前面的符号可以出现零次或多次，但在第一次可能的匹配时停止（最短））
;1. (your ending string - the dot needed to be escaped, otherwise it would mean any character)
1。（你的结束字符串 - 需要转义的点，否则就意味着任何字符）

#2

You need to use RegEx, with an expression like "rgm(.);1\.". That's just off the top of my head, you will have to verify the exact regular expression that matches your pattern. Then, use RegEx.Replace() with it.

您需要使用RegEx，其表达式为“rgm（。）; 1 \。”。这只是我的头脑，你必须验证与你的模式匹配的确切正则表达式。然后，使用RegEx.Replace（）。

#1