vi搜索复制粘贴搜索副本

I was just wondering if anyone could help out with how to do the following using vi.

我只是想知道是否有人可以帮助如何使用vi执行以下操作。

I have a text file and it might contain something like

我有一个文本文件,它可能包含类似的东西

start of text file:
--something1.something2--
--anotherThing1.something2--
end of text file:

If I want to take this line and convert it by way of searching for anything matching the first occurrence of [A-Za-z0-9] copy that to the buffer then append it on the same line to before the first occurrent of --

如果我想取这行并通过搜索与第一次出现的[A-Za-z0-9]副本匹配到缓冲区的任何内容进行转换,然后将它附加到第一个出现之前的同一行 -

start of text file:
--something1.something2.something1--
--anotherThing1.something2.anotherThing1--
end of text file:

Is there a single VI command to do this?

是否有一个VI命令来执行此操作?

Cheers Ben

4 个解决方案

#1

:%s/--\([a-zA-Z0-9]*\).\(.*\)--/--\1.\2.\1--/gc

or without asking confirmation for every replace:

或者没有要求确认每次更换:

:%s/--\([a-zA-Z0-9]*\).\(.*\)--/--\1.\2.\1--/g

will produce:

--something1.something2.something1--
--anotherThing1.something2.anotherThing1--

from:

--something1.something2--
--anotherThing1.something2--

This is if you want to copy the first word after '--' up to first '.' and append '.' and word found before the last '--'.

如果你想复制' - '之后的第一个单词,直到第一个'。'。并追加'。'和最后一个' - '之前找到的单词。

Using vim.

RE COMMENTS:

Someone mentioned that it will not work when there are multiple words and so on. I tested it on the following:

有人提到当有多个单词时它不起作用等等。我测试了以下内容:

start of text file:
--something1.something2.something3.something4.something5.something6--
--anotherThing1.something2.anotherThing3.anotherThing4.anotherThing5--
end of text file:

after replace with the above expression:

用以上表达式替换后:

start of text file:
--something1.something2.something3.something4.something5.something6.something1--
--anotherThing1.something2.anotherThing3.anotherThing4.anotherThing5.anotherThing1--
end of text file:

#2

Try this:

%s:\([A-Za-z0-9]\+\)\(\..\+\)--:\1\2.\1--:g

#3

Holy crap, in the time it took me to login to post that answer, you posted it and already got a comment!

神圣的废话,在我登录发布答案的时候,你发布了它并且已经有了评论!

%s/--\(\w*\)\.\(.*\)--/--\1.\2.\1--/g

--ab1.cd2..yz99-- -> --ab1.cd2..yz99.ab1--

--ab1.cd2..yz99-- - > --ab1.cd2..yz99.ab1--

#4

Building on stefanB's solution but using negated character classes and the "very magic" setting, I arrive at the following substitution command:

在stefanB的解决方案的基础上,但使用否定的字符类和“非常神奇”的设置,我得到以下替换命令:

:%s/\v--([^.]+)\.(.*)--/--\1.\2.\1--/

Depending on the exact requirements (what are allowed characters for "something1" and "anotherThing1") this might or might not be more correct.

根据具体要求(“something1”和“anotherThing1”允许的字符),这可能会或可能不会更正确。

One more thing to consider: all solutions posted so far assume that there is only one occurance of the "--text.someOtherText-- pattern per line. If this is not the case, the (.*) part of the pattern would have to be adjusted and the /g modifier is required.

还有一件事需要考虑:到目前为止发布的所有解决方案都假设每行只有一个“--text.someOtherText--模式”。如果不是这种情况,模式的(。*)部分会有要调整,需要/ g修饰符。

#1

:%s/--\([a-zA-Z0-9]*\).\(.*\)--/--\1.\2.\1--/gc