在多个任务访问的函数内保留非静态变量值

Iif I have a function defined:

如果我定义了一个函数:

int32_t function(const bool inDebugPattern)
{
  char tempBuff[256]; memset(tempBuff, 0, sizeof tempBuff);

  /* use tempBuff[] */
}

which is called by multiple tasks, will the memory allocation of tempBuff[] be separate(unique) for each call of this function or will it be shared and can be corrupted by a concurrent call from other tasks?

由多个任务调用,tempBuff []的内存分配对于此函数的每次调用都是独立的(唯一的),还是会被共享,并且可能被其他任务的并发调用破坏?

1 个解决方案

#1

Since tempBuff is a local variable it will be unique for each function call

由于tempBuff是一个局部变量,因此每个函数调用都是唯一的

Take a look at C Scope rules

看看C Scope规则

#1