Below is the following line of code I use to replace an HTML break tag with a carriage return. However, I have other HTML symbols that I need to replace and when I call this line of code again, with different parameters, it's as if the first one is overwritten. Is there a way I can include multiple parameters? Is there a more efficient way to do this in Swift? For example: replace both br> with "" and nbsp with "".
下面是我用来用回车符替换HTML break标记的以下代码行。但是,我还需要替换其他HTML符号,当我再次调用这行代码时,使用不同的参数,就像第一个被覆盖一样。有没有办法可以包含多个参数?在Swift中有更有效的方法吗?例如:将br>替换为“”,将nbsp替换为“”。
textView.text = content.stringByReplacingOccurrencesOfString("<br /><br />", withString:"\r")
4 个解决方案
#1
12
Use replacingOccurrences along with a the String.CompareOptions.regularExpresion option.
使用replacementOccurrences和String.CompareOptions.regularExpresion选项。
Example (Swift 3):
示例(Swift 3):
var x = "<Hello, [play^ground+]>"
let y = x.replacingOccurrences(of: "[\\[\\]^+<>]", with: "7", options: .regularExpression, range: nil)
print(y)
Input characters which are to be replaced inside the square brackets like so [\\ Characters]
在方括号内输入要输入的字符,如[\\字符]
Output:
输出:
7Hello, 7play7ground777
#2
7
I solved it based on the idea of Rosetta Code
我根据Rosetta Code的想法解决了这个问题
extension String {
func stringByRemovingAll(characters: [Character]) -> String {
return String(self.characters.filter({ !characters.contains($0) }))
}
func stringByRemovingAll(subStrings: [String]) -> String {
var resultString = self
subStrings.map { resultString = resultString.stringByReplacingOccurrencesOfString($0, withString: "") }
return resultString
}
}
Example:
例:
let str = "Hello, *"
let chars: [Character] = ["a", "e", "i"]
let myStrings = ["Hello", ", ", "overflow"]
let newString = str.stringByRemovingAll(chars)
let anotherString = str.stringByRemovingAll(myStrings)
Result, when printed:
结果,打印时:
newString: Hllo, stckovrflow
newString:Hllo,stckovrflow
anotherString: stack
anotherString:stack
#3
6
As @matt mentioned you are starting over with the same content
string. The stringByReplacingOccurrencesOfString method doesn't actually change anything in the original content
string. It returns to you a new string with the replacement changes while content
remains unchanged.
正如@matt所提到的,你将重新开始使用相同的内容字符串。 stringByReplacingOccurrencesOfString方法实际上不会更改原始内容字符串中的任何内容。当内容保持不变时,它会返回一个包含替换更改的新字符串。
Something like this should work for you
这样的事情对你有用
let result1 = content.stringByReplacingOccurrencesOfString("<br /><br />", withString:"\r")
let result2 = result1.stringByReplacingOccurrencesOfString(" ", withString:" ")
textView.text = result2
#4
1
extension String {
var html2AttributedString:NSAttributedString {
return NSAttributedString(data: dataUsingEncoding(NSUTF8StringEncoding)!, options:[NSDocumentTypeDocumentAttribute:NSHTMLTextDocumentType, NSCharacterEncodingDocumentAttribute: NSUTF8StringEncoding], documentAttributes: nil, error: nil)!
}
}
let myHtmlCode = "<style type=\"text/css\">#red{color:#F00}#green{color:#0F0}#blue{color: #00F}</style><span id=\"red\" >Red</span> <span id=\"green\" >Green</span><span id=\"blue\">Blue</span>"
myHtmlCode.html2AttributedString
#1
12
Use replacingOccurrences along with a the String.CompareOptions.regularExpresion option.
使用replacementOccurrences和String.CompareOptions.regularExpresion选项。
Example (Swift 3):
示例(Swift 3):
var x = "<Hello, [play^ground+]>"
let y = x.replacingOccurrences(of: "[\\[\\]^+<>]", with: "7", options: .regularExpression, range: nil)
print(y)
Input characters which are to be replaced inside the square brackets like so [\\ Characters]
在方括号内输入要输入的字符,如[\\字符]
Output:
输出:
7Hello, 7play7ground777
#2
7
I solved it based on the idea of Rosetta Code
我根据Rosetta Code的想法解决了这个问题
extension String {
func stringByRemovingAll(characters: [Character]) -> String {
return String(self.characters.filter({ !characters.contains($0) }))
}
func stringByRemovingAll(subStrings: [String]) -> String {
var resultString = self
subStrings.map { resultString = resultString.stringByReplacingOccurrencesOfString($0, withString: "") }
return resultString
}
}
Example:
例:
let str = "Hello, *"
let chars: [Character] = ["a", "e", "i"]
let myStrings = ["Hello", ", ", "overflow"]
let newString = str.stringByRemovingAll(chars)
let anotherString = str.stringByRemovingAll(myStrings)
Result, when printed:
结果,打印时:
newString: Hllo, stckovrflow
newString:Hllo,stckovrflow
anotherString: stack
anotherString:stack
#3
6
As @matt mentioned you are starting over with the same content
string. The stringByReplacingOccurrencesOfString method doesn't actually change anything in the original content
string. It returns to you a new string with the replacement changes while content
remains unchanged.
正如@matt所提到的,你将重新开始使用相同的内容字符串。 stringByReplacingOccurrencesOfString方法实际上不会更改原始内容字符串中的任何内容。当内容保持不变时,它会返回一个包含替换更改的新字符串。
Something like this should work for you
这样的事情对你有用
let result1 = content.stringByReplacingOccurrencesOfString("<br /><br />", withString:"\r")
let result2 = result1.stringByReplacingOccurrencesOfString(" ", withString:" ")
textView.text = result2
#4
1
extension String {
var html2AttributedString:NSAttributedString {
return NSAttributedString(data: dataUsingEncoding(NSUTF8StringEncoding)!, options:[NSDocumentTypeDocumentAttribute:NSHTMLTextDocumentType, NSCharacterEncodingDocumentAttribute: NSUTF8StringEncoding], documentAttributes: nil, error: nil)!
}
}
let myHtmlCode = "<style type=\"text/css\">#red{color:#F00}#green{color:#0F0}#blue{color: #00F}</style><span id=\"red\" >Red</span> <span id=\"green\" >Green</span><span id=\"blue\">Blue</span>"
myHtmlCode.html2AttributedString