i saw some example code for finding members of list. so i changed it slightly and converged for fit to me, however it doesn't work
我看到了一些用于查找列表成员的示例代码。所以我稍微改变它并收敛以适应我,但它不起作用
screen_name <-"Newsminster"
api.url <- paste0("https://api.twitter.com/1.1/lists/list.json?","screen_name=", screen_name)
url.get=GET(api.url)
url.content=content(url.get, as="text")
output :
输出:
url.content [1] "{\"errors\":[{\"code\":215,\"message\":\"Bad Authentication data.\"}]}"
url.content [1]“{\”errors \“:[{\”code \“:215,\”message \“:\”Bad Authentication data。\“}]}”
1 个解决方案
#1
0
it looks like Twitter's latest API 1.1 does not allow access without authentication
看起来Twitter的最新API 1.1不允许在没有身份验证的情况下进行访问
The article can be found here:
这篇文章可以在这里找到:
http://www.webdevdoor.com/php/authenticating-twitter-feed-timeline-oauth/
http://www.webdevdoor.com/php/authenticating-twitter-feed-timeline-oauth/
check this answer as well
检查这个答案
Reference
参考
Twitter API错误215
#1
0
it looks like Twitter's latest API 1.1 does not allow access without authentication
看起来Twitter的最新API 1.1不允许在没有身份验证的情况下进行访问
The article can be found here:
这篇文章可以在这里找到:
http://www.webdevdoor.com/php/authenticating-twitter-feed-timeline-oauth/
http://www.webdevdoor.com/php/authenticating-twitter-feed-timeline-oauth/
check this answer as well
检查这个答案
Reference
参考
Twitter API错误215