I want to make a bash script that will get a bunch of urls from a mysql table and pass all the urls one by one to the wget --spider , and update the mysql with the response code from wget: "HTTP request sent, awaiting response... 200 OK" I really don't know where to start from .. Thank you
我想创建一个bash脚本,它将从mysql表中获取一堆url并将所有url一个接一个地传递给wget --spider,并使用wget的响应代码更新mysql:“发送HTTP请求,等待回答... 200 OK“我真的不知道从哪里开始......谢谢
1 个解决方案
#1
0
#!/bin/bash
DBNAME=DB_NAME
USER=USER
PASS=PASS
HOST=localhost
STATEMENT="select name from environment;"
COUNTER=$(mysql $DBNAME -h $HOST -u$USER -p$PASS -e "$STATEMENT")
for entry in $COUNTER; do
echo wget $entry
done
Here is the output
这是输出
./mql.sh
wget name
wget Prod
wget uat
#1
0
#!/bin/bash
DBNAME=DB_NAME
USER=USER
PASS=PASS
HOST=localhost
STATEMENT="select name from environment;"
COUNTER=$(mysql $DBNAME -h $HOST -u$USER -p$PASS -e "$STATEMENT")
for entry in $COUNTER; do
echo wget $entry
done
Here is the output
这是输出
./mql.sh
wget name
wget Prod
wget uat