What does it mean, in particular symbol * after end?
它是什么意思，尤其是结束后的符号* ?
LOG=/root/$(basename $0).log
_notlogged(){
if ! grep -q "# $*" $LOG; then
echo "no"
fi
echo "yes"
}
_notlogged
Therefore, are grep regex rules special?
因此，grep regex规则是否特殊?
1 个解决方案
#1
2
The double quoted string "# $*" is subject to bash's parameter expansion before it get's passed to grep.
在传递给grep之前，双引号字符串“# $*”会受到bash的参数扩展。
$* is a special variable in bash, it contains all positional parameters. Meaning the arguments to _notlogged.
$*是bash中的一个特殊变量，它包含所有位置参数。表示参数为_notlog。
If you call it like
如果你这样称呼它。
_lotlogged foo
the expression passed to grep would be
传递给grep的表达式将是
grep -q "# foo"
Check the bash manual for further information.
查看bash手册了解更多信息。
#1
2
The double quoted string "# $*" is subject to bash's parameter expansion before it get's passed to grep.
在传递给grep之前，双引号字符串“# $*”会受到bash的参数扩展。
$* is a special variable in bash, it contains all positional parameters. Meaning the arguments to _notlogged.
$*是bash中的一个特殊变量，它包含所有位置参数。表示参数为_notlog。
If you call it like
如果你这样称呼它。
_lotlogged foo
the expression passed to grep would be
传递给grep的表达式将是
grep -q "# foo"
Check the bash manual for further information.
查看bash手册了解更多信息。