I Love You Too HDU 2816

Description

This is a true story. A man showed his love to a girl,but the girl didn't replied clearly ,just gave him a Morse Code: 
****-/*----/----*/****-/****-/*----/---**/*----/****-/*----/-****/***--/****-/*----/----*/**---/-****/**---/**---/***--/--***/****-/   He was so anxious that he asked for help in the Internet and after one day a girl named "Pianyi angel" found the secret of this code. She translate this code as this five steps: 
1.First translate the morse code to a number string: 4194418141634192622374
2.Second she cut two number as one group 41 94 41 81 41 63 41 92 62 23 74,according to standard Mobile phone can get this alphabet:GZGTGOGXNCS

3.Third she change this alphabet according to the keyboard: QWERTYUIOPASDFGHJKLZXCVBNM = ABCDEFGHIJKLMNOPQRSTUVWXYZ
So ,we can get OTOEOIOUYVL
4.Fourth, divide this alphabet to two parts: OTOEOI and OUYVL, compose again.we will get OOTUOYEVOLI
5.Finally,reverse this alphabet the answer will appear : I LOVE YOU TOO

I guess you might worship Pianyi angel as me,so let's Orz her. 
Now,the task is translate the number strings. 

Input

A number string each line(length <= 1000). I ensure all input are legal.

Output

An upper alphabet string.

Sample Input

4194418141634192622374
41944181416341926223

Sample Output

ILOVEYOUTOO
VOYEUOOTIO

#include<iostream>
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<queue>
using namespace std;

int main()
{
    char ss[],s[];
    char* a[]={"ABC","DEF","GHI","JKL","MNO","PQRS","TUV","WXYZ"};
    char b[]="KXVMCNOPHQRSZYIJADLEGWBUFT";
    char d[]="QWERTYUIOPASDFGHJKLZXCVBNM";
    //for(int i=0;i<26;i++)
    //    cout<<b[d[i]-'A']<<" ";
    while(gets(ss))
    {
        int m=strlen(ss);
        int len=;
        for(int i=;i<m;i++)
            if(ss[i]!=' ')
                s[len++]=ss[i];
        char s0[];
        int x=;
        for(int i=;i<len;i+=)
        {
            s0[x++]=b[a[s[i]-''][s[i+]-'']-'A'];

        }
        char s1[];
        int y=;
        for(int i=;i<x;i+=)
        {
            s1[i]=s0[y++];
        }
        for(int i=;i<x;i+=)
        {
            s1[i]=s0[y++];
        }
        for(int i=y-;i>=;i--)
        {
            putchar(s1[i]);
        }
        printf("\n");
    }
}