从字符串中删除数组中的短语。

I need to remove some phrases from a string in Ruby. The phrases are defined inside an array. It could look like this:

我需要从Ruby中的字符串中删除一些短语。短语在数组中定义。它可能是这样的:

remove = ["Test", "Another One", "Something Else"]

Then I want to check and remove these from a given string.

然后我要检查并从给定的字符串中删除它们。

"This is a Test" => "This is a " "This is Another One" => "This is " "This is Another Two" => "This is Another Two"

"这是一个测试" => "这是"这是另一个" => "这是"这是另外两个" => "这是另外两个"

Using Ruby 1.9.3 and Rail 3.2.6.

使用Ruby 1.9.3和rails 3.2.6。

2 个解决方案

ary = ["Test", "Another One", "Something Else", "(RegExp i\s escaped)"]
string.gsub(Regexp.union(ary), '')

Regexp.union can be used to compile an array of strings (or regexpes) into a single regexp which therefore only requires a single search & replace.

Regexp。可以使用union将字符串数组(或regexpes)编译为一个regexp，因此只需要一个搜索和替换。

Regexp.union ['string', /regexp?/i] #=> /string|(?i-mx:regexp?)/

Simplest (but not most efficient):

最简单的(但不是最有效的):

# Non-mutating
cleaned = str
remove.each{ |s| cleaned = cleaned.gsub(s,'') }

# Mutating
remove.each{ |s| str.gsub!(s,'') }

More efficient (but less clear):

更有效率(但不太清楚):

# Non-mutating
cleaned = str.gsub(Regexp.union(remove), '')

# Mutating
str.gsub!(Regexp.union(remove), '')

ary = ["Test", "Another One", "Something Else", "(RegExp i\s escaped)"]
string.gsub(Regexp.union(ary), '')