有人可以帮助我提高这段代码的效率吗?

时间:2022-05-22 01:33:29

I'm creating a skill tree calculator for a game. I wrote a method that checks whether or not it can subtract a point from the skill and then proceeds to do so. Everything is working as it should, however it's very slow when this method is executed in rapid succession (i.e. when 5 points are subtract at the same time).

我正在为游戏创建一个技能树计算器。我写了一个方法,检查它是否可以从技能中减去一个点然后继续这样做。一切都按预期工作,但是当这种方法快速连续执行时(即同时减去5个点),速度非常慢。

Can anyone help me with this and more important explain why certain things are faster and what to avoid?

任何人都可以帮助我,更重要的是解释为什么某些事情会更快以及应该避免什么?

Here is the method:

这是方法:

public void cmdSubtractPoint(int index, SkillTree tree) {

    boolean subtract = false;

    if (this.blueTree.get(index).getInvestedPoints() != 0) {
        //Only subtract a point if the skill isn't empty

        if (index == 0 || index == 1) {
            if ((((this.blueTree.get(0).getInvestedPoints() + this.blueTree.get(1).getInvestedPoints()) - 1) < 5)
                    && ((this.blueTree.get(2).getInvestedPoints() + this.blueTree.get(3).getInvestedPoints() +
                    this.blueTree.get(4).getInvestedPoints() + this.blueTree.get(5).getInvestedPoints() + this.blueTree.get(6).getInvestedPoints()) != 0)) {
                this.showToast();
            } else if ((((this.blueTree.get(0).getInvestedPoints() + this.blueTree.get(1).getInvestedPoints()) + this.blueTree.get(2).getInvestedPoints() + this.blueTree.get(3).getInvestedPoints() - 1) < 10)
                    && ((this.blueTree.get(4).getInvestedPoints() + this.blueTree.get(5).getInvestedPoints() + this.blueTree.get(6).getInvestedPoints()) != 0)) {
                this.showToast();
            } else if ((((this.blueTree.get(0).getInvestedPoints() + this.blueTree.get(1).getInvestedPoints()) + this.blueTree.get(2).getInvestedPoints() + this.blueTree.get(3).getInvestedPoints() + this.blueTree.get(4).getInvestedPoints() + this.blueTree.get(5).getInvestedPoints() - 1) < 15)
                    && ((this.blueTree.get(6).getInvestedPoints()) != 0)) {
                this.showToast();
            } else {
                subtract = true;
            }
        } else if (index == 2 || index == 3) {
            if ((((this.blueTree.get(0).getInvestedPoints() + this.blueTree.get(1).getInvestedPoints()) + this.blueTree.get(2).getInvestedPoints() + this.blueTree.get(3).getInvestedPoints() - 1) < 10)
                    && ((this.blueTree.get(4).getInvestedPoints() + this.blueTree.get(5).getInvestedPoints() + this.blueTree.get(6).getInvestedPoints()) != 0)) {
                this.showToast();
            } else if ((((this.blueTree.get(0).getInvestedPoints() + this.blueTree.get(1).getInvestedPoints()) + this.blueTree.get(2).getInvestedPoints() + this.blueTree.get(3).getInvestedPoints() + this.blueTree.get(4).getInvestedPoints() + this.blueTree.get(5).getInvestedPoints() - 1) < 15)
                    && ((this.blueTree.get(6).getInvestedPoints()) != 0)) {
                this.showToast();
            } else {
                subtract = true;
            }
        } else if (index == 4 || index == 5) {
            if ((((this.blueTree.get(0).getInvestedPoints() + this.blueTree.get(1).getInvestedPoints()) + this.blueTree.get(2).getInvestedPoints() + this.blueTree.get(3).getInvestedPoints() + this.blueTree.get(4).getInvestedPoints() + this.blueTree.get(5).getInvestedPoints() - 1) < 15)
                    && ((this.blueTree.get(6).getInvestedPoints()) != 0)) {
                this.showToast();
            } else {
                subtract = true;
            }
        } else if (index == 6) {
                subtract = true;
        }

        if (subtract) {
            this.pointsInBlueTree -= 1;
            this.blueTree.get(index).subtractPoint();
        }

    }
}

1 个解决方案

#1


0  

If reduce value calculation to one time and use switch, you will obtain code similar this:

如果将值计算减少到一次并使用开关,您将获得类似的代码:

public void cmdSubtractPoint(int index, SkillTree tree) {

        boolean subtract = false;

        if (this.blueTree.get(index).getInvestedPoints() != 0) {
            // Only subtract a point if the skill isn't empty
            int temp01 = this.blueTree.get(0).getInvestedPoints() + tree.blueTree.get(1).getInvestedPoints();
            int temp23 = this.blueTree.get(2).getInvestedPoints() + tree.blueTree.get(3).getInvestedPoints();
            int temp45 = this.blueTree.get(4).getInvestedPoints() + tree.blueTree.get(5).getInvestedPoints();
            int temp6 = this.blueTree.get(6).getInvestedPoints();

            switch (index) {
            case 0:
            case 1:
                if (((temp01 ) < 6) && ((temp23 + temp45 + temp6) != 0)) {
                    this.showToast();
                } else if (((temp01 + temp23) < 11) && ((temp45 + temp6) != 0)) {
                    this.showToast();
                } else if (((temp01 + temp23 + temp45) < 16) && (temp6 != 0)) {
                    this.showToast();
                } else {
                    subtract = true;
                }
                break;
            case 2:
            case 3:
                if (((temp01 + temp23) < 11) && ((temp45 + temp6) != 0)) {
                    this.showToast();
                } else if (((temp01 + temp23 + temp45) < 16) && (temp6 != 0)) {
                    this.showToast();
                } else {
                    subtract = true;
                }
                break;
            case 4:
            case 5:
                if (((temp01 + temp23 + temp45) < 16) && (temp6 != 0)) {
                    this.showToast();
                } else {
                    subtract = true;
                }
                break;
            case 6:
                subtract = true;
                break;
            }

            if (subtract) {
                this.pointsInBlueTree -= 1;
                this.blueTree.get(index).subtractPoint();
            }

        }
    }

#1


0  

If reduce value calculation to one time and use switch, you will obtain code similar this:

如果将值计算减少到一次并使用开关,您将获得类似的代码:

public void cmdSubtractPoint(int index, SkillTree tree) {

        boolean subtract = false;

        if (this.blueTree.get(index).getInvestedPoints() != 0) {
            // Only subtract a point if the skill isn't empty
            int temp01 = this.blueTree.get(0).getInvestedPoints() + tree.blueTree.get(1).getInvestedPoints();
            int temp23 = this.blueTree.get(2).getInvestedPoints() + tree.blueTree.get(3).getInvestedPoints();
            int temp45 = this.blueTree.get(4).getInvestedPoints() + tree.blueTree.get(5).getInvestedPoints();
            int temp6 = this.blueTree.get(6).getInvestedPoints();

            switch (index) {
            case 0:
            case 1:
                if (((temp01 ) < 6) && ((temp23 + temp45 + temp6) != 0)) {
                    this.showToast();
                } else if (((temp01 + temp23) < 11) && ((temp45 + temp6) != 0)) {
                    this.showToast();
                } else if (((temp01 + temp23 + temp45) < 16) && (temp6 != 0)) {
                    this.showToast();
                } else {
                    subtract = true;
                }
                break;
            case 2:
            case 3:
                if (((temp01 + temp23) < 11) && ((temp45 + temp6) != 0)) {
                    this.showToast();
                } else if (((temp01 + temp23 + temp45) < 16) && (temp6 != 0)) {
                    this.showToast();
                } else {
                    subtract = true;
                }
                break;
            case 4:
            case 5:
                if (((temp01 + temp23 + temp45) < 16) && (temp6 != 0)) {
                    this.showToast();
                } else {
                    subtract = true;
                }
                break;
            case 6:
                subtract = true;
                break;
            }

            if (subtract) {
                this.pointsInBlueTree -= 1;
                this.blueTree.get(index).subtractPoint();
            }

        }
    }