i'm trying to run one c executable file using php exec().
我正在尝试使用php exec()运行一个c可执行文件。
When c contains a simple program like print hello. I'm using
当c包含一个简单的程序,如打印你好。我在用着
exec('./print.out')
It's working fine. But when I need to pass a argument to my c program I'm using
它工作正常。但是当我需要将参数传递给我正在使用的c程序时
exec('./arugment.out -n 1234')
It is not working. Can any body tell me how to pass arugment using exec to c program.
它不起作用。任何人都可以告诉我如何使用exec将程序传递给c程序。
1 个解决方案
#1
4
From taking a look at the php documentation, it appears that exec treats arguments a bit oddly. You could try doing
从看看php文档看来,exec看起来有点奇怪。你可以试试
exec("./argument.out '-n 1234'")
to prevent it from mangling them (it normally separates them all on space, which might be what's messing it up).
防止它被破坏(它通常将它们全部分隔在空间上,这可能会使它变得混乱)。
#1
4
From taking a look at the php documentation, it appears that exec treats arguments a bit oddly. You could try doing
从看看php文档看来,exec看起来有点奇怪。你可以试试
exec("./argument.out '-n 1234'")
to prevent it from mangling them (it normally separates them all on space, which might be what's messing it up).
防止它被破坏(它通常将它们全部分隔在空间上,这可能会使它变得混乱)。