在Node.js中获取父目录名称

I am using Node.js, and I want to obtain the parent directory name for a file. I have the file "../test1/folder1/FolderIWant/test.txt".

我正在使用Node.js，我想获取文件的父目录名称。我有文件“../test1/folder1/FolderIWant/test.txt”。

I want to get "FolderIWant".

我想得到“FolderIWant”。

I have tried:

我努力了：

var path = require('path');
var parentDir = path.dirname(filename);

But it returns ../test1/folder1/FolderIWant.

但它返回../test1/folder1/FolderIWant。

2 个解决方案

#1

Use split() and pop():

使用split（）和pop（）：

path.dirname(filename).split(path.sep).pop()

#2

What you want is path.basename:

你想要的是path.basename：

path.basename(path.dirname(filename))