如何使用角度中的请求正文发送url模板参数?

时间:2021-04-30 23:58:56

Suppose I have a resource set up like this:

假设我有一个这样的资源设置:

resource = $resource(
    "http://foo.com/service/:type/:id",
    {},
    {save: {method:'PUT', params: {type:'@type', id: '@id'}}}
);
resource.save({type:'user', id:14, name:'Bob Dole'});

Is there any way I can prevent type and id from being submitted as part of the request body, and just send name in the PUT payload? I don't control the API I am submitting to, and it seems to not like the extra parameters I am sending it.

有什么办法可以阻止类型和id作为请求体的一部分提交,只是在PUT有效负载中发送名称?我不控制我提交的API,它似乎不喜欢我发送它的额外参数。

Thanks!

谢谢!

Update - 10/25/13 - 13:38

更新 - 2013年10月25日 - 13:38

The documentation for resource says this:

资源文档说:

If the parameter value is prefixed with @ then the value of that parameter is extracted from the data object (useful for non-GET operations).

如果参数值以@为前缀,则从数据对象中提取该参数的值(对非GET操作很有用)。

That implies that this ought to remove the parameters from the data:

这意味着这应该从数据中删除参数:

resource.save({type:'@user', id:'@14', name:'Bob Dole'});

but it doesn't seem to work. Still at a loss.

但它似乎没有用。还是不知所措。

2 个解决方案

#1


33  

Use the first parameter for your url template parameters and put your post data in the second parameter like this:

使用第一个参数作为您的网址模板参数,并将您的发布数据放在第二个参数中,如下所示:

resource.save({id:14, type:'user'}, {name:'Bob Dole'});

Here's the line from the Angular docs that shows the function signature:

以下是Angular文档中显示函数签名的行:

non-GET "class" actions: Resource.action([parameters], postData, [success], [error])

非GET“类”动作:Resource.action([parameters],postData,[success],[error])

Here's an example in plunker

这是一个关于plunker的例子

The request you get does not have the url parameters in the body:

您获得的请求在正文中没有url参数:

Request URL:http://run.plnkr.co/JAOqZqW6RSywatUM/badUrl/user/14
Request Method:PUT
Request Payloadview source
{name:Bob Dole}

#2


7  

FWIW, I did find a workaround, thanks to @Reboog711, by including a transformRequest parameter like so:

FWIW,我确实找到了一个解决方法,感谢@ Reboog711,通过包含一个transformRequest参数,如下所示:

resource = $resource(
    "http://foo.com/service/:type/:id",
    {},
    {save: {
        method:'PUT', 
        transformRequest:function(data) {
            delete data.type;
            delete data.id;
            return JSON.stringify(data);
        },
        params: {type:'@type', id: '@id'}
    }}
);

#1


33  

Use the first parameter for your url template parameters and put your post data in the second parameter like this:

使用第一个参数作为您的网址模板参数,并将您的发布数据放在第二个参数中,如下所示:

resource.save({id:14, type:'user'}, {name:'Bob Dole'});

Here's the line from the Angular docs that shows the function signature:

以下是Angular文档中显示函数签名的行:

non-GET "class" actions: Resource.action([parameters], postData, [success], [error])

非GET“类”动作:Resource.action([parameters],postData,[success],[error])

Here's an example in plunker

这是一个关于plunker的例子

The request you get does not have the url parameters in the body:

您获得的请求在正文中没有url参数:

Request URL:http://run.plnkr.co/JAOqZqW6RSywatUM/badUrl/user/14
Request Method:PUT
Request Payloadview source
{name:Bob Dole}

#2


7  

FWIW, I did find a workaround, thanks to @Reboog711, by including a transformRequest parameter like so:

FWIW,我确实找到了一个解决方法,感谢@ Reboog711,通过包含一个transformRequest参数,如下所示:

resource = $resource(
    "http://foo.com/service/:type/:id",
    {},
    {save: {
        method:'PUT', 
        transformRequest:function(data) {
            delete data.type;
            delete data.id;
            return JSON.stringify(data);
        },
        params: {type:'@type', id: '@id'}
    }}
);