插入并更新到多个表，MySQL

I've got two tables. I want to, when submitting a form, use parentcreate.php as action and with that file insert a couple of variables into the first table and at the same time update the other table with one of the variables. I've searched online but the closest thing I found was inserting and updating a single table, not two different.

我有两张桌子。我想在提交表单时使用parentcreate.php作为操作,并使用该文件在第一个表中插入几个变量,同时用其中一个变量更新另一个表。我在网上搜索过,但我发现最接近的是插入和更新单个表,而不是两个不同的表。

Thanks in advance.

提前致谢。

Update:

Here's the code I've got so far, as you can see it's just inserting into the first table.

这是我到目前为止的代码,因为你可以看到它只是插入到第一个表中。

session_name('knine_settings_login');
    session_set_cookie_params(1*1*1*15*60);
    session_start();

    mysql_connect('xxxx', 'xxxx', 'xxxx') or die(mysql_error());
    mysql_select_db("xxxx") or die(mysql_error());

    $ClassIDOne = mysql_real_escape_string($_POST["cidone"]);
    $ClassIDTwo = mysql_real_escape_string($_POST["cidtwo"]);
    $ClassIDThree = mysql_real_escape_string($_POST["cidthree"]);
    $ClassIDFour = mysql_real_escape_string($_POST["cidfour"]);
    $ClassIDFive = mysql_real_escape_string($_POST["cidfive"]);
    $usr = $_SESSION["usr"];

    mysql_query("SET NAMES 'utf8'") or die(mysql_error()); 
    mysql_query("SET CHARACTER SET 'utf8'") or die(mysql_error()); 

    $query="INSERT INTO knine_parent_db
            SET usr = '$usr', ClassIDOne = '$ClassIDOne', ClassIDTwo = '$ClassIDTwo', ClassIDThree = '$ClassIDThree', ClassIDFour = '$ClassIDFour', ClassIDFive = '$ClassIDFive'";

I basically want to execute both these queries at the same time:

我基本上想要同时执行这两个查询:

$query="INSERT INTO knine_parent_db
            SET usr = '$usr', ClassIDOne = '$ClassIDOne', ClassIDTwo = '$ClassIDTwo', ClassIDThree = '$ClassIDThree', ClassIDFour = '$ClassIDFour', ClassIDFive = '$ClassIDFive'";

    $query="UPDATE knine_settings_login
            SET ClassID = '$usr' WHERE usr ='$usr'";

2 个解决方案

#1

You should use PDO, and read this topic in PHP manual : Link to PDO::beginTransaction and this one and this one too

你应该使用PDO,并在PHP手册中阅读这个主题:链接到PDO :: beginTransaction以及这个和这一个

You should begin a new transaction, then do your requests, check if there was no error, then commit !

你应该开始一个新的交易,然后做你的请求,检查是否没有错误,然后提交!

Once you use PDO::commit, the queries are backed to auto-commit mode, then you have to use again PDO::beginTransaction to set auto-commit off and do multiple queries into a single transaction.

一旦您使用PDO :: commit,查询将被备份为自动提交模式,那么您必须再次使用PDO :: beginTransaction来设置自动提交并对单个事务执行多个查询。

That how to do multiple requests in one transaction.

如何在一个事务中执行多个请求。

In your case, there is some code to help you :

在您的情况下,有一些代码可以帮助您:

$query1 = "INSERT INTO knine_parent_db
          SET usr = :usr,
              ClassIDOne = :ClassIDOne,
              ClassIDTwo = :ClassIDTwo,
              ClassIDThree = :ClassIDThree,
              ClassIDFour = :ClassIDFour,
              ClassIDFive = :ClassIDFive
          ";

$exec1 = [
    ':usr' => $_SESSION["usr"],
    ':ClassIDOne' => $_POST["cidone"],
    ':ClassIDTwo' => $_POST["cidtwo"],
    ':ClassIDThree' => $_POST["cidthree"],
    ':ClassIDFour' => $_POST["cidfour"],
    ':ClassIDFive' => $_POST["cidfive"],
];

$query2 = "UPDATE knine_settings_login
           SET ClassID = :usr
           WHERE usr = :usr
          ";

$exec2 = [':usr' => $_SESSION["usr"]];

$db_host = 'localhost';
$db_name = 'MyDatabase';
$db_user = 'user';
$db_pass = 'password';

$dsn = 'mysql:host='.$db_host.';dbname='.$db_name.';charset=utf8';

try
{
    $PDO = new PDO($dsn, $db_user, $db_pass);
}
catch(PDOException $e)
{
    // if dev mode
    echo 'Database connection error : ' . $e->getMessage();

    // if prod mode
    //header('Location: /404.html');
    //exit;
}

// begin of transaction
$PDO->beginTransaction();

$res1 = $PDO->prepare($query1);
$res2 = $PDO->prepare($query2);

if($res1->execute($exec1) && $res2->execute($exec2))
{
    $PDO->commit();
}
else
{
    $PDO->rollBack();
}

// end of transaction

#2

Try and separate the statements this worked for me

尝试并分离这对我有用的陈述

//  insert query execution
$sql = "INSERT INTO vendors (vendorId ,vendor_name, address, email, phone, category) VALUES
('$vendorId', '$vendor_name', '$address', '$email',
 '$phone', '$category')
";

if ($mysqli - > query($sql) === true) {
  echo "<script>alert('You have successfully registered');</script>";
} else {
  echo "<script>alert('could not create shop something went wrong  ');  <
  /script>";  
  $mysqli - > error;
}

//  update query execution
$sql = "UPDATE users SET userType = 'vendor', vendor_name='$vendor_name'  
WHERE id = '".$_SESSION['
id ']."'
";

if ($mysqli - > query($sql) === true) {
  echo "<script>alert('update successfull ');</script>";
  header("location:my-account.php");
} else {
  echo "<script>alert('could not create shop something went wrong  ');  <
  /script>";  $mysqli->error;
}

#1