CREATE TABLE `feeds` (
`FEED_ID` bigint(20) unsigned NOT NULL AUTO_INCREMENT,
`P_ID` bigint(20) NOT NULL,
`P_NAME` varchar(100) NOT NULL,
PRIMARY KEY (`P_ID`),
UNIQUE KEY `FEED_ID` (`FEED_ID`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8
::
INSERT INTO `table_a` (`P_ID`,`P_NAME`) VALUES ('30','John')
ON DUPLICATE KEY UPDATE `P_ID`= VALUES(`P_ID`),`P_NAME`= VALUES(`P_NAME`);
I would like to use INSERT.. ON DUPLICATE KEY UPDATE where anytime I create that insert, I'd like the FEED_ID to auto increment. As for now it stays the same because there was no new row insertion...
我想使用INSERT .. ON DUPLICATE KEY UPDATE,无论何时我创建该插入,我都希望FEED_ID自动增加。至于它现在保持不变,因为没有新的行插入......
Should I delete then insert?
我应该删除然后插入?
1 个解决方案
#1
3
It would seem like you're looking for REPLACE
instead of INSERT ... ON DUPLICATE KEY
; it will remove the old row if one exists with a conflicting primary key or unique key, and insert a new one with a new FEED_ID
;
看起来你正在寻找REPLACE而不是INSERT ...在DUPLICATE KEY;如果存在具有冲突的主键或唯一键的旧行,它将删除旧行,并插入具有新FEED_ID的新行;
REPLACE INTO feeds (p_id,p_name) VALUES (1,'Olle');
一个要测试的SQLfiddle。
#1
3
It would seem like you're looking for REPLACE
instead of INSERT ... ON DUPLICATE KEY
; it will remove the old row if one exists with a conflicting primary key or unique key, and insert a new one with a new FEED_ID
;
看起来你正在寻找REPLACE而不是INSERT ...在DUPLICATE KEY;如果存在具有冲突的主键或唯一键的旧行,它将删除旧行,并插入具有新FEED_ID的新行;
REPLACE INTO feeds (p_id,p_name) VALUES (1,'Olle');
一个要测试的SQLfiddle。