I'm trying to insert some mock payment info into a dev database with this query:
我正在尝试将一些模拟支付信息插入到一个dev数据库中,并使用该查询:
INSERT
INTO
Payments(Amount)
VALUES(12.33)
WHERE
Payments.CustomerID = '145300';
How can adjust this to execute? I also tried something like this:
如何调整这个执行?我也尝试过这样的方法:
IF NOT EXISTS(
SELECT
1
FROM
Payments
WHERE
Payments.CustomerID = '145300'
) INSERT
INTO
Payments(Amount)
VALUES(12.33);
5 个解决方案
#1
2
I think you are trying to do an update statement (set amount = 12.33 for customer with ID = 145300)
我认为您正在尝试做一个update语句(对于ID = 145300的客户,设置amount = 12.33)
UPDATE Payments
SET Amount = 12.33
WHERE CustomerID = '145300'
Else if you are trying to insert a new row then you have to use
否则,如果要插入新行,就必须使用
IF NOT EXISTS(SELECT 1 FROM Payments WHERE CustomerID = '145300')
INSERT INTO Payments(CustomerID,Amount)
VALUES('145300',12.33)
Or if you want to combine both command (if customer exists do update else insert new row)
或者如果您想合并两个命令(如果客户存在,请更新else,插入新行)
IF NOT EXISTS(SELECT 1 FROM Payments WHERE CustomerID = '145300')
INSERT INTO Payments(CustomerID,Amount)
VALUES('145300',12.33)
ELSE
UPDATE Payments
SET Amount = 12.33
WHERE CustomerID = '145300'
#2
2
If you want to insert new rows with the given CustomerID
如果您想用给定的id插入新的行
INSERT
INTO
Payments(Amount,CustomerID )
VALUES(12.33,'145300');
else if you already have payment for the customer you can do:
否则,如果你已经为客户付款,你可以:
UPDATE
Payments
SET Amount = 12.33
WHERE
CustomerID = '145300';
#3
1
It sounds like having the customerID already set. In that case you should use an update statement to update a row. Insert statements will add a completely new row which can not contain a value.
听起来似乎已经设置了customerID。在这种情况下,您应该使用update语句来更新一行。Insert语句将添加一个不能包含值的全新行。
#4
1
Do you want to perform update;
是否需要执行更新;
update Payments set Amount = 12.33 where Payments.CustomerID = '145300'
#5
0
Ok, looks like I actually need to just do an insert into the Payments table that has the correct CustomerID, as there are currently no Payments with that CustomerID, so I cannot update it.
好的,看起来我实际上需要对具有正确CustomerID的付款表进行插入,因为目前没有使用该CustomerID的付款,所以我不能更新它。
I ran INSERT INTO Payments (CustomerID, Amount, PaymentTypeID) Values ('145300', 24.99, 8);
and then SELECT * FROM Payments WHERE Payments.CustomerID = '145300';
to confirm and we're in business. Thanks everyone!
我运行INSERT INTO Payments (CustomerID、金额、PaymentTypeID) value ('145300', 24.99, 8);然后从支付中选择*。CustomerID = ' 145300 ';确认一下,我们是做生意的。谢谢大家!
#1
2
I think you are trying to do an update statement (set amount = 12.33 for customer with ID = 145300)
我认为您正在尝试做一个update语句(对于ID = 145300的客户,设置amount = 12.33)
UPDATE Payments
SET Amount = 12.33
WHERE CustomerID = '145300'
Else if you are trying to insert a new row then you have to use
否则,如果要插入新行,就必须使用
IF NOT EXISTS(SELECT 1 FROM Payments WHERE CustomerID = '145300')
INSERT INTO Payments(CustomerID,Amount)
VALUES('145300',12.33)
Or if you want to combine both command (if customer exists do update else insert new row)
或者如果您想合并两个命令(如果客户存在,请更新else,插入新行)
IF NOT EXISTS(SELECT 1 FROM Payments WHERE CustomerID = '145300')
INSERT INTO Payments(CustomerID,Amount)
VALUES('145300',12.33)
ELSE
UPDATE Payments
SET Amount = 12.33
WHERE CustomerID = '145300'
#2
2
If you want to insert new rows with the given CustomerID
如果您想用给定的id插入新的行
INSERT
INTO
Payments(Amount,CustomerID )
VALUES(12.33,'145300');
else if you already have payment for the customer you can do:
否则,如果你已经为客户付款,你可以:
UPDATE
Payments
SET Amount = 12.33
WHERE
CustomerID = '145300';
#3
1
It sounds like having the customerID already set. In that case you should use an update statement to update a row. Insert statements will add a completely new row which can not contain a value.
听起来似乎已经设置了customerID。在这种情况下,您应该使用update语句来更新一行。Insert语句将添加一个不能包含值的全新行。
#4
1
Do you want to perform update;
是否需要执行更新;
update Payments set Amount = 12.33 where Payments.CustomerID = '145300'
#5
0
Ok, looks like I actually need to just do an insert into the Payments table that has the correct CustomerID, as there are currently no Payments with that CustomerID, so I cannot update it.
好的,看起来我实际上需要对具有正确CustomerID的付款表进行插入,因为目前没有使用该CustomerID的付款,所以我不能更新它。
I ran INSERT INTO Payments (CustomerID, Amount, PaymentTypeID) Values ('145300', 24.99, 8);
and then SELECT * FROM Payments WHERE Payments.CustomerID = '145300';
to confirm and we're in business. Thanks everyone!
我运行INSERT INTO Payments (CustomerID、金额、PaymentTypeID) value ('145300', 24.99, 8);然后从支付中选择*。CustomerID = ' 145300 ';确认一下,我们是做生意的。谢谢大家!