PLpgSQL函数用于查找给定表中仅具有NULL值的列

时间:2021-01-16 22:55:42

We have to find columns of a table with only NULL values. We are trying to build a plpgsql function that takes a table's name and returns the list of such columns.

我们必须找到只有NULL值的表的列。我们正在尝试构建一个plpgsql函数,它接受一个表的名称并返回这些列的列表。

How to create such a function?

如何创建这样的功能?

We are using PgAdmin 1.16.

我们正在使用PgAdmin 1.16。

1 个解决方案

#1


2  

You can query the catalog table pg_attribute to get a list of columns which are not defined NOT NULL and therefore can hold NULL values:

您可以查询目录表pg_attribute以获取未定义NOT NULL的列的列表,因此可以保存NULL值:

SELECT quote_ident(attname) AS column_can_be_null
FROM   pg_attribute
WHERE  attrelid = 'tbl'::regclass -- valid, visible table name 
AND    attnum >= 1                -- exclude tableoid & friends
AND    NOT attisdropped           -- exclude dropped columns
AND    NOT attnotnull             -- exclude columns defined NOT NULL!
ORDER  BY attnum;

Where tbl is your (optionally schema-qualified) table name.

其中tbl是您的(可选的模式限定的)表名。

Doesn't say there are any actual NULL values in the column. You'd have to test each column. Like this:

不要说列中有任何实际的NULL值。你必须测试每一列。像这样:

Full automation with plpgsql function

CREATE OR REPLACE FUNCTION f_all_null_columns_of_tbl(_tbl regclass)
  RETURNS SETOF text AS
$func$
DECLARE
   _row_ct  bigint;        -- count rows in table $1
   _sql     text;          -- SQL string to test for NULL values
   _cols    text[];        -- array of candidate column names
   _nulls   bool[];        -- array of test results
BEGIN

EXECUTE 'SELECT count(*) FROM ' || _tbl
INTO _row_ct;

IF _row_ct = 0 THEN
   RAISE EXCEPTION 'Table % has no rows!', _tbl;  -- pointless for empty table
ELSE
   RAISE NOTICE '% rows in table %.', _row_ct, _tbl; 
END IF;

SELECT INTO _sql, _cols
      'SELECT ARRAY[' || string_agg('bool_and(' || col || ' IS NULL)', ', ')
       || '] FROM ' || _tbl
    , array_agg(col)
FROM  (
   SELECT quote_ident(attname) AS col
   FROM   pg_attribute
   WHERE  attrelid = _tbl            -- valid, visible table name 
   AND    attnum >= 1                -- exclude tableoid & friends
   AND    NOT attisdropped           -- exclude dropped columns
   AND    NOT attnotnull             -- exclude columns defined NOT NULL!
   ORDER  BY attnum
   ) sub;

EXECUTE _sql INTO _nulls;

FOR i IN 1 .. array_upper(_cols, 1)
LOOP
   IF _nulls[i] THEN                 -- column is NULL in all rows
      RETURN NEXT _cols[i];
   END IF;
END LOOP;

RETURN;
END
$func$ LANGUAGE plpgsql;

Call:

SELECT f_all_null_columns_of_tbl('my_schema.my_table');

Tested with Postgres 9.1 and 9.3.
This uses a number of advanced plpgsql features.

使用Postgres 9.1和9.3进行测试。这使用了许多高级plpgsql功能。

SQL Fiddle.

Related answer building SQL code and executing it, with modern syntax:

相关答案使用现代语法构建SQL代码并执行它:

About traversing a record:

关于遍历记录:

#1


2  

You can query the catalog table pg_attribute to get a list of columns which are not defined NOT NULL and therefore can hold NULL values:

您可以查询目录表pg_attribute以获取未定义NOT NULL的列的列表,因此可以保存NULL值:

SELECT quote_ident(attname) AS column_can_be_null
FROM   pg_attribute
WHERE  attrelid = 'tbl'::regclass -- valid, visible table name 
AND    attnum >= 1                -- exclude tableoid & friends
AND    NOT attisdropped           -- exclude dropped columns
AND    NOT attnotnull             -- exclude columns defined NOT NULL!
ORDER  BY attnum;

Where tbl is your (optionally schema-qualified) table name.

其中tbl是您的(可选的模式限定的)表名。

Doesn't say there are any actual NULL values in the column. You'd have to test each column. Like this:

不要说列中有任何实际的NULL值。你必须测试每一列。像这样:

Full automation with plpgsql function

CREATE OR REPLACE FUNCTION f_all_null_columns_of_tbl(_tbl regclass)
  RETURNS SETOF text AS
$func$
DECLARE
   _row_ct  bigint;        -- count rows in table $1
   _sql     text;          -- SQL string to test for NULL values
   _cols    text[];        -- array of candidate column names
   _nulls   bool[];        -- array of test results
BEGIN

EXECUTE 'SELECT count(*) FROM ' || _tbl
INTO _row_ct;

IF _row_ct = 0 THEN
   RAISE EXCEPTION 'Table % has no rows!', _tbl;  -- pointless for empty table
ELSE
   RAISE NOTICE '% rows in table %.', _row_ct, _tbl; 
END IF;

SELECT INTO _sql, _cols
      'SELECT ARRAY[' || string_agg('bool_and(' || col || ' IS NULL)', ', ')
       || '] FROM ' || _tbl
    , array_agg(col)
FROM  (
   SELECT quote_ident(attname) AS col
   FROM   pg_attribute
   WHERE  attrelid = _tbl            -- valid, visible table name 
   AND    attnum >= 1                -- exclude tableoid & friends
   AND    NOT attisdropped           -- exclude dropped columns
   AND    NOT attnotnull             -- exclude columns defined NOT NULL!
   ORDER  BY attnum
   ) sub;

EXECUTE _sql INTO _nulls;

FOR i IN 1 .. array_upper(_cols, 1)
LOOP
   IF _nulls[i] THEN                 -- column is NULL in all rows
      RETURN NEXT _cols[i];
   END IF;
END LOOP;

RETURN;
END
$func$ LANGUAGE plpgsql;

Call:

SELECT f_all_null_columns_of_tbl('my_schema.my_table');

Tested with Postgres 9.1 and 9.3.
This uses a number of advanced plpgsql features.

使用Postgres 9.1和9.3进行测试。这使用了许多高级plpgsql功能。

SQL Fiddle.

Related answer building SQL code and executing it, with modern syntax:

相关答案使用现代语法构建SQL代码并执行它:

About traversing a record:

关于遍历记录: