I am getting an exception like as
我有个例外
java.sql.SQLException: Before start of result set when calling getInt() method
My code is as follows:::
我的代码如下:
public void setdateTOSource(){
try{
String q = "SELECT * FROM ipp.resource;";
ResultSet result = DB_Access.getData(q);
System.out.println("Size result set"+result.getFetchSize());
while(result.next()){
getIpSource().add(result.getString(1));
System.out.println(result.getString(1));
}
System.out.println("source size "+getIpSource().size());
}
catch(Exception e){
System.out.println(e);
}
}
public void insertTargetToDb(List<String> targetValue){
try{
Connection con = DB_Connect.getDataBaseConnection();
Statement statement1 = con.createStatement();
int val=0;
String q1 = "SELECT MAX(area_id) as aa FROM ipp.area;";
ResultSet resultset = statement1.executeQuery(q1);
if(resultset.next()){
val = resultset.getInt(1);
};
val++;
String q2 = "INSERT INTO ipp.area VALUES("+val+",'"+getAreaName()+"',1);";
Statement statement2 = con.createStatement();
statement1.executeUpdate(q2);
for( int y=0;y<targetValue.size();y++){
System.out.println("FS");
String ip=targetValue.get(y);
System.out.println("ip" +ip);
String q3 ="SELECT resource_id FROM ipp.resource r where ip_address like '"+ip+"%';";
Statement statement3 = con.createStatement();
ResultSet resultset3 =statement3.executeQuery(q3);
System.out.println("FS1");
// ResultSet result1 =DB_Access.getData(q3);
System.out.println("FS2");
System.out.println("result set"+resultset3.getFetchSize());
//====================================================================
while(resultset3.next()){
setId(resultset.getInt(1));
}
System.out.println("result :........."+resultset3.getInt("resource_id"));
System.out.println("FS3");
String q4 = "INSERT INTO ipp.used_resource VALUES("+val+","+getId()+");";
Statement statement4= con.createStatement();
statement4.executeUpdate(q4);
// DB_Access.setData(q3);
statement3.close();
statement4.close();
// resultset3.close();
}
resultset.close();
statement1.close();
statement2.close();
con.close();
addMessage("Area created Successfully");
}
catch(Exception e){
System.out.println(e);
}
}
Exception comes after line
异常后线
//========================== resource_id is an integer value
/ / = = = = = = = = = = = = = = = = = = = = = = = = = = resource_id是一个整数值
1 个解决方案
#1
3
This line
这条线
while(resultset3.next()){
setId(resultset.getInt(1));
}
must be replaced with?
必须更换?
while(resultset3.next()){
setId(resultset3.getInt(1));
}
#1
3
This line
这条线
while(resultset3.next()){
setId(resultset.getInt(1));
}
must be replaced with?
必须更换?
while(resultset3.next()){
setId(resultset3.getInt(1));
}