Sql按多列排序

I've the below result

我有以下结果

VendorName | IncidentID | IncidentStatus | IncidentDate
-------------------------------------------------------
XYZ        | 100        |     Open       | 02-JUN-2011    
XYZ        | 101        |     Open       | 03-JUN-2011  
ABC        | 102        |     Open       | 01-JUN-2011  
XYZ        | 103        |     Open       | 01-APR-2011  
ABC        | 105        |     Open       | 05-JUN-2011

I want to order VendorName which has latest incident. Vendor ABC has the latest incident hence it should come first with all other incident for same vendor and then next Vendor with all respective incident in descending order.The desired result is like this -

我想订购最新事件的VendorName。供应商ABC有最新的事件，因此它应该首先与同一供应商的所有其他事件，然后下一个供应商与所有相应的事件降序。期望的结果是这样的 -

VendorName | IncidentID | IncidentStatus | IncidentDate  
-------------------------------------------------------
ABC        | 105        |     Open       | 05-JUN-2011 
ABC        | 102        |     Open       | 01-JUN-2011
XYZ        | 101        |     Open       | 03-JUN-2011 
XYZ        | 100        |     Open       | 02-JUN-2011    
XYZ        | 103        |     Open       | 01-APR-2011

ORDER BY IncidentDate desc, VendorName doesn't give the desired output. Any help ?

ORDER BY IncidentDate desc，VendorName不提供所需的输出。有帮助吗？

4 个解决方案

#1

Use analytic functions:

使用分析函数：

SELECT *
FROM(
    SELECT 
        VendorName, 
        IncidentID, 
        IncidentStatus, 
        IncidentDate, 
        MAX(IncidentDate) OVER (PARTITION BY VendorName) maxDate
    FROM yourTable
) t
ORDER BY t.maxDate DESC, t.VendorName ASC, t.IncidentDate DESC

Refer to: http://docs.oracle.com/javadb/10.8.2.2/ref/rrefsqlj13658.html http://docs.oracle.com/cd/E11882_01/server.112/e10592/functions003.htm http://docs.oracle.com/cd/E11882_01/server.112/e26088/functions004.htm

请参阅：http：//docs.oracle.com/javadb/10.8.2.2/ref/rrefsqlj13658.html http://docs.oracle.com/cd/E11882_01/server.112/e10592/functions003.htm http：/ /docs.oracle.com/cd/E11882_01/server.112/e26088/functions004.htm

#2

This will do it ...

这样做......

ORDER BY MAX(INCIDENTDATE) OVER (PARTITION BY VENDORNAME) DESC, INCIDENTDATE DESC

... but I'm not sure if the analytic function is allowed in the ORDER BY. If it isn't, calculate it in a subquery and order by in the main query ...

...但我不确定ORDER BY中是否允许使用分析函数。如果不是，请在子查询中计算并在主查询中按顺序排序...

select ...
from   (
  select Max(incidentdate) over (partition by vendorname) max_incidentdate_by_vendor,
         ...)
order by max_incidentdate_by_vender desc, incidentdate desc

#3

If you are on a RAC installation

如果您使用的是RAC安装

set linesize 300
column REDOLOG_FILE_NAME format a50
SELECT
    a.INST_ID,
    a.GROUP#,
    a.THREAD#,
    a.SEQUENCE#,
    a.ARCHIVED,
    a.STATUS,
    b.MEMBER    AS REDOLOG_FILE_NAME,
    (a.BYTES/1024/1024/1024) AS SIZE_GB
FROM gv$log a
JOIN gv$logfile b ON a.Group#=b.Group# 
AND a.INST_ID=b.INST_ID 
ORDER BY a.INST_ID ASC, a.GROUP# ASC;

#4

-2

select vendorname, incidentid, incidentstatus, incidentdate, max(incidentdate) 
over (partition by vendorname order by incidentdate desc) max_incidentdate
from t1 order by max_incidentdate desc, incidentdate desc

#1