I would like to group my results by one column (NAME), then order by a second column (NOTE) for each group, and finally order the groups by the highest NOTE they have.
我想将我的结果分组为一列(NAME),然后按每个组的第二列(注释)排序,最后按照最高的顺序对组进行排序。
So, if my entities are scrambled like these:
所以,如果我的实体像这样扰乱:
NAME NOTE
Andrew 19
Thomas 18
Andrew 18
Andrew 17
Frank 16
Frank 15
Thomas 14
Thomas 12
Frank 5
I would like them to be ordered like this:
我希望他们这样订购:
NAME NOTE
Andrew 19
Andrew 18
Andrew 17
Thomas 18
Thomas 14
Thomas 12
Frank 16
Frank 15
Frank 5
grouped by name, with Andrew appearing first because his highest note is 19, then Thomas (18) and Frank (16).
按姓名分组,安德鲁首先出现因为他的最高音符是19,然后是托马斯(18)和弗兰克(16)。
Regards,
Val
4 个解决方案
#1
3
CTE answer...
Create Table NameNoteTable (Name Varchar(10), Note Int);
Insert NameNoteTable
Select 'Andrew', 19
Union All
Select 'Andrew', 18
Union All
Select 'Andrew', 17
Union All
Select 'Thomas', 18
Union All
Select 'Thomas', 14
Union All
Select 'Thomas', 12
Union All
Select 'Frank', 16
Union All
Select 'Frank', 15;
With cte As
(
Select Row_Number() Over (Order By Max(Note) Desc) As tID,
Name,
Max(Note) As MaxNote
From NameNoteTable
Group By Name
)
Select nnt.Name, nnt.Note
From NameNoteTable nnt
Join cte c
On nnt.Name = c.Name
Order By tID, Note Desc;
#2
3
Here is a way to do it using window functions:
以下是使用窗口函数执行此操作的方法:
select name, note
from (select t.*, max(note) over (partition by name) as maxnote
from t
) t
order by maxnote desc, name
In addition to ordering by the maxnote, it also orders by the name. If there are ties, then it keeps all the records for a given name together.
除了通过maxnote订购外,它还按名称订购。如果存在联系,则它将给定名称的所有记录保存在一起。
#3
1
SELECT t.name, t.note
FROM @tbl t
ORDER BY (SELECT MAX(note) FROM @tbl WHERE name = t.name) DESC
, name
, note DESC
This is the simplest way, using PARTITION BY is only slightly more syntax and on larger tables would likely run more efficiently.
这是最简单的方法,使用PARTITION BY只是稍微多一点的语法,在较大的表上可能会更有效地运行。
#4
0
Very simple way:
很简单的方法:
select name, note from NameNoteTable order by name asc, note desc
选择名称,注释来自NameNoteTable的名称asc,注意desc
#1
3
CTE answer...
Create Table NameNoteTable (Name Varchar(10), Note Int);
Insert NameNoteTable
Select 'Andrew', 19
Union All
Select 'Andrew', 18
Union All
Select 'Andrew', 17
Union All
Select 'Thomas', 18
Union All
Select 'Thomas', 14
Union All
Select 'Thomas', 12
Union All
Select 'Frank', 16
Union All
Select 'Frank', 15;
With cte As
(
Select Row_Number() Over (Order By Max(Note) Desc) As tID,
Name,
Max(Note) As MaxNote
From NameNoteTable
Group By Name
)
Select nnt.Name, nnt.Note
From NameNoteTable nnt
Join cte c
On nnt.Name = c.Name
Order By tID, Note Desc;
#2
3
Here is a way to do it using window functions:
以下是使用窗口函数执行此操作的方法:
select name, note
from (select t.*, max(note) over (partition by name) as maxnote
from t
) t
order by maxnote desc, name
In addition to ordering by the maxnote, it also orders by the name. If there are ties, then it keeps all the records for a given name together.
除了通过maxnote订购外,它还按名称订购。如果存在联系,则它将给定名称的所有记录保存在一起。
#3
1
SELECT t.name, t.note
FROM @tbl t
ORDER BY (SELECT MAX(note) FROM @tbl WHERE name = t.name) DESC
, name
, note DESC
This is the simplest way, using PARTITION BY is only slightly more syntax and on larger tables would likely run more efficiently.
这是最简单的方法,使用PARTITION BY只是稍微多一点的语法,在较大的表上可能会更有效地运行。
#4
0
Very simple way:
很简单的方法:
select name, note from NameNoteTable order by name asc, note desc
选择名称,注释来自NameNoteTable的名称asc,注意desc