I have 2 columns on my add_membership page. The left column is 'Memberships added' and the right column is 'Memberships too add'.
我的add_membership页面上有2列。左栏是“会员已添加”,右栏是“会员已添加”。
The code to present the 'memberships to add' is:
呈现“要添加的成员资格”的代码是:
$credit=mysql_query("SELECT * FROM credit");
while($rowc=mysql_fetch_assoc($credit)){
$credit_id=$rowc['credit_id'];
if(in_array($credit_id, $_SESSION['pa']))
{}else{
$url_log=$rowc['logo_url'];
$name=$rowc['name'];
?>
<form action="#" method="post">
<div class="text_right"><input type="submit" value="Add"
name="asubmit" class="search_input_submit" /></div>
<?php echo "<img src='$url_log' width='50' height='50' alt='$name' title='$name'>"; ?>
<input type="checkbox" value="<?php echo $credit_id; ?>" name="credit_id" />
<strong><?php echo $name; ?></strong><br />
Membership Number:<input type="text" name"membership">
</form><br /><br />
<?php
}
}
?>
As you can see the Membership number input.
如您所见,可以看到会员编号输入。
This is the code i've been trying to get to work to add the Membership Number:
这是我一直试图添加会员号码的代码:
<?php
if($_POST['asubmit']){
$credit_id_add=$_POST['credit_id'];
$membership=$_POST['membership'];
mysql_query("INSERT INTO accreditation VALUES(NULL, $lid, $credit_id_add,
'$membership','0' )");
echo $membership ;
$credit_id_add=null;
$referer = $_SERVER['HTTP_REFERER'];
echo "<meta http-equiv='refresh' content='1; url=$referer'> ";
}
?>
I have 'echo'd' the variables I need to save and they all appear except for the 'Membership' which is why the error is occurring because it's trying to find the $membership value.
我已经'回应'我需要保存的变量,除了'Membership'之外它们都出现了,这就是为什么错误发生的原因,因为它试图找到$ membership值。
For the top section of the code, I have had to include the Credit ID into a checkbox as it doesn't seem to work by me just echo'ing for the $_POST to pick up, or putting it in a hidden text field.
对于代码的顶部部分,我必须将Credit ID包含在一个复选框中,因为它似乎不起作用,只需回显$ _POST来拾取或将其放入隐藏文本字段中。
Any light shed on this would be hugely appreciated.
任何关于此的光线都将受到极大的赞赏。
Thanks in advance.
提前致谢。
3 个解决方案
#1
2
You are missing an =
in your HTML:
你在HTML中缺少一个=:
<input type="text" name"membership">
should be:
应该:
<input type="text" name="membership">
#2
1
If the first block of code is being used, you're also not closing the else condition:
如果正在使用第一个代码块,那么您也没有关闭else条件:
else{
$url_log=$rowc['logo_url'];
$name=$rowc['name'];
?>
Should be:
应该:
else {
$url_log = $rowc['logo_url'];
$name = $rowc['name'];
}
?>
There should also be a }
before the closing PHP tag to close the while loop. I'm not sure if that was just missed in a copy/paste from your page, but if it's in your code, fixing that will help.
在关闭PHP标记之前还应该有一个}来关闭while循环。我不确定是否只是在页面的复制/粘贴中错过了,但如果它在您的代码中,那么修复它将有所帮助。
Like this:
喜欢这个:
<?php
$credit = mysql_query("SELECT * FROM credit");
while ($rowc = mysql_fetch_assoc($credit)) {
$credit_id = $rowc['credit_id'];
if (!in_array($credit_id, $_SESSION['pa'])) {
$url_log = $rowc['logo_url'];
$name = $rowc['name'];
}
}
?>
#3
0
General tip:
一般提示:
Instead of doing
而不是做
if (some condition you only need when it's false) {
} else {
... do stuff here ...
}
just write
写吧
if (!some condition...) {
... do stuff here ...
}
Note the !
, which is a logical negation, aka "not". It makes it far more explicit that you only want to deal with "false" conditions, and didn't just forget to fill in the "true" portion.
注意!,这是一个逻辑否定,又名“不”。它更明确地表明你只想处理“错误”条件,并且不要忘记填写“真实”部分。
#1
2
You are missing an =
in your HTML:
你在HTML中缺少一个=:
<input type="text" name"membership">
should be:
应该:
<input type="text" name="membership">
#2
1
If the first block of code is being used, you're also not closing the else condition:
如果正在使用第一个代码块,那么您也没有关闭else条件:
else{
$url_log=$rowc['logo_url'];
$name=$rowc['name'];
?>
Should be:
应该:
else {
$url_log = $rowc['logo_url'];
$name = $rowc['name'];
}
?>
There should also be a }
before the closing PHP tag to close the while loop. I'm not sure if that was just missed in a copy/paste from your page, but if it's in your code, fixing that will help.
在关闭PHP标记之前还应该有一个}来关闭while循环。我不确定是否只是在页面的复制/粘贴中错过了,但如果它在您的代码中,那么修复它将有所帮助。
Like this:
喜欢这个:
<?php
$credit = mysql_query("SELECT * FROM credit");
while ($rowc = mysql_fetch_assoc($credit)) {
$credit_id = $rowc['credit_id'];
if (!in_array($credit_id, $_SESSION['pa'])) {
$url_log = $rowc['logo_url'];
$name = $rowc['name'];
}
}
?>
#3
0
General tip:
一般提示:
Instead of doing
而不是做
if (some condition you only need when it's false) {
} else {
... do stuff here ...
}
just write
写吧
if (!some condition...) {
... do stuff here ...
}
Note the !
, which is a logical negation, aka "not". It makes it far more explicit that you only want to deal with "false" conditions, and didn't just forget to fill in the "true" portion.
注意!,这是一个逻辑否定,又名“不”。它更明确地表明你只想处理“错误”条件,并且不要忘记填写“真实”部分。