在eval()的d代码中，意外的$结尾

I hate to ask such a specific question, but I'm getting an error I can't figure out. This is in a cron job which runs on the hour. I'm creating an array of tasks, each of which has a date check which is supposed to be eval()'d.

我讨厌问这么具体的问题，但我犯了一个我搞不懂的错误。这是一项正常的工作。我正在创建一个任务数组，每个任务都有一个日期检查，它应该是eval()'d。

$todo = array();
$todo[] = array( "date('z')%3 == 0", "Task 1" );
$todo[] = array( "date('N') == 1", "Task 2" );
foreach( $todo as $task )
{
    if( eval($task[0]) ) {
        echo $task[1];
    }
}

For some reason the eval() line is giving me this error. Note that I am getting this error for both tasks.

出于某种原因，eval()行给了我这个错误。注意，我在这两个任务中都得到了这个错误。

Parse error: syntax error, unexpected $end in /file.php(21) : eval()'d code on line 1

Any suggestions? I tried searching for this but couldn't find anything. Thank you.

有什么建议吗?我试着找这个，但什么也没找到。谢谢你！

1 个解决方案

#1

eval only accepts statements, not expressions. You need to convert your tests with:

eval只接受语句，不接受表达式。您需要将您的测试转换为:

if (eval("return $task[0];")) {