C+ 11:错误:“begin”不是“std”的成员

I am trying to do the following operation:

我正在做以下操作:

source = new int[10];
dest =  new int[10];
std::copy( std::begin(source), std::end(source), std::begin(dest));

However, the compiler reports the following error.

但是，编译器报告如下错误。

copy.cpp:5434:14: error: ‘begin’ is not a member of ‘std’
copy.cpp:5434:44: error: ‘end’ is not a member of ‘std’
copy.cpp:5434:72: error: ‘begin’ is not a member of ‘std’

I have included the required <iterator> header in the code. Can anybody help me on this?

我在代码中包含了所需的头。有人能帮我吗?

3 个解决方案

#1

Template functions std::begin() and std::end() are not implemented for pointers (pointers do not contain information about the number of elements they refer to) Instead them you should write

模板函数std::begin()和std: end()不是为指针实现的(指针不包含它们引用的元素数量的信息)，而是您应该编写的

std::copy( source, source + 10, dest);

As for the error you should check whether you included header

至于错误，您应该检查是否包含了header。

#include <iterator>

Also maybe your compiler does not support the C++ 2011 Standard.

也许你的编译器不支持c++ 2011标准。

#2

In addition to include <iterator>in C++11 enabled compiler. You should know begin/end are not useful for pointers, they're useful for arrays:

此外，在c++ 11启用的编译器中还包括。你应该知道开始/结束对指针没有用处，它们对数组有用:

int source[10];
int dest[10];

std::copy(std::begin(source), std::end(source), std::begin(dest));

#3

-1

also have this problem when using g++ compiler this code in linux.

在linux中使用g++编译器时也有这个问题。

Using g++ compiler that contain C++ featuer should add C++11 flag

使用包含c++特性的g++编译器应该添加c++ 11标志

g++ -std=c++11 -o test test.cpp

#1