What is the best way to convert a string to hex and vice versa in C++?
在c++中,将字符串转换为十六进制的最好方法是什么?
Example:
例子:
- A string like
"Hello World"
to hex format:48656C6C6F20576F726C64
- 像“Hello World”这样的字符串,以hex格式:48656C6C6F20576F726C64。
- And from hex
48656C6C6F20576F726C64
to string:"Hello World"
- 从hex 48656C6C6F20576F726C64到字符串:“Hello World”
10 个解决方案
#1
64
A string like "Hello World" to hex format: 48656C6C6F20576F726C64.
像“Hello World”这样的字符串,以hex格式:48656C6C6F20576F726C64。
Ah, here you go:
啊,给你:
#include <string>
std::string string_to_hex(const std::string& input)
{
static const char* const lut = "0123456789ABCDEF";
size_t len = input.length();
std::string output;
output.reserve(2 * len);
for (size_t i = 0; i < len; ++i)
{
const unsigned char c = input[i];
output.push_back(lut[c >> 4]);
output.push_back(lut[c & 15]);
}
return output;
}
#include <algorithm>
#include <stdexcept>
std::string hex_to_string(const std::string& input)
{
static const char* const lut = "0123456789ABCDEF";
size_t len = input.length();
if (len & 1) throw std::invalid_argument("odd length");
std::string output;
output.reserve(len / 2);
for (size_t i = 0; i < len; i += 2)
{
char a = input[i];
const char* p = std::lower_bound(lut, lut + 16, a);
if (*p != a) throw std::invalid_argument("not a hex digit");
char b = input[i + 1];
const char* q = std::lower_bound(lut, lut + 16, b);
if (*q != b) throw std::invalid_argument("not a hex digit");
output.push_back(((p - lut) << 4) | (q - lut));
}
return output;
}
(This assumes that a char has 8 bits, so it's not very portable, but you can take it from here.)
(这假设一个字符有8位,所以它不是很便携,但您可以从这里获取。)
#2
26
string ToHex(const string& s, bool upper_case /* = true */)
{
ostringstream ret;
for (string::size_type i = 0; i < s.length(); ++i)
ret << std::hex << std::setfill('0') << std::setw(2) << (upper_case ? std::uppercase : std::nouppercase) << (int)s[i];
return ret.str();
}
int FromHex(const string &s) { return strtoul(s.c_str(), NULL, 16); }
#3
9
You can try this. It's Working...
你可以试试这个。它的工作…
#include <algorithm>
#include <sstream>
#include <iostream>
#include <iterator>
#include <iomanip>
namespace {
const std::string test="hello world";
}
int main() {
std::ostringstream result;
result << std::setw(2) << std::setfill('0') << std::hex << std::uppercase;
std::copy(test.begin(), test.end(), std::ostream_iterator<unsigned int>(result, " "));
std::cout << test << ":" << result.str() << std::endl;
}
#4
7
Simplest example using the Standard Library.
使用标准库的最简单的例子。
#include <iostream>
using namespace std;
int main()
{
char c = 'n';
cout << "HEX " << hex << (int)c << endl; // output in hexadecimal
cout << "ASC" << c << endl; // output in ascii
return 0;
}
To check the output, codepad returns: 6e
为了检查输出,codepad返回:6e。
and an online ascii-to-hexadecimal conversion tool yields 6e as well. So it works.
同时,一个在线的ascii-十六进制转换工具也能产生6e。所以它的工作原理。
You can also do this:
你也可以这样做:
template<class T> std::string toHexString(const T& value, int width) {
std::ostringstream oss;
oss << hex;
if (width > 0) {
oss << setw(width) << setfill('0');
}
oss << value;
return oss.str();
}
#5
7
Using lookup tables and the like works, but is just overkill, here are some very simple ways of taking a string to hex and hex back to a string:
使用查找表和类似的工作,但只是过度使用,这里有一些非常简单的方法,可以将字符串以十六进制和十六进制的形式返回到字符串:
#include <stdexcept>
#include <sstream>
#include <iomanip>
#include <string>
#include <cstdint>
std::string string_to_hex(const std::string& in) {
std::stringstream ss;
ss << std::hex << std::setfill('0');
for (size_t i = 0; in.length() > i; ++i) {
ss << std::setw(2) << static_cast<unsigned int>(static_cast<unsigned char>(in[i]));
}
return ss.str();
}
std::string hex_to_string(const std::string& in) {
std::string output;
if ((in.length() % 2) != 0) {
throw std::runtime_error("String is not valid length ...");
}
size_t cnt = in.length() / 2;
for (size_t i = 0; cnt > i; ++i) {
uint32_t s = 0;
std::stringstream ss;
ss << std::hex << in.substr(i * 2, 2);
ss >> s;
output.push_back(static_cast<unsigned char>(s));
}
return output;
}
#6
6
This is a bit faster:
这有点快:
static const char* s_hexTable[256] =
{
"00", "01", "02", "03", "04", "05", "06", "07", "08", "09", "0a", "0b", "0c", "0d", "0e", "0f", "10", "11",
"12", "13", "14", "15", "16", "17", "18", "19", "1a", "1b", "1c", "1d", "1e", "1f", "20", "21", "22", "23",
"24", "25", "26", "27", "28", "29", "2a", "2b", "2c", "2d", "2e", "2f", "30", "31", "32", "33", "34", "35",
"36", "37", "38", "39", "3a", "3b", "3c", "3d", "3e", "3f", "40", "41", "42", "43", "44", "45", "46", "47",
"48", "49", "4a", "4b", "4c", "4d", "4e", "4f", "50", "51", "52", "53", "54", "55", "56", "57", "58", "59",
"5a", "5b", "5c", "5d", "5e", "5f", "60", "61", "62", "63", "64", "65", "66", "67", "68", "69", "6a", "6b",
"6c", "6d", "6e", "6f", "70", "71", "72", "73", "74", "75", "76", "77", "78", "79", "7a", "7b", "7c", "7d",
"7e", "7f", "80", "81", "82", "83", "84", "85", "86", "87", "88", "89", "8a", "8b", "8c", "8d", "8e", "8f",
"90", "91", "92", "93", "94", "95", "96", "97", "98", "99", "9a", "9b", "9c", "9d", "9e", "9f", "a0", "a1",
"a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "aa", "ab", "ac", "ad", "ae", "af", "b0", "b1", "b2", "b3",
"b4", "b5", "b6", "b7", "b8", "b9", "ba", "bb", "bc", "bd", "be", "bf", "c0", "c1", "c2", "c3", "c4", "c5",
"c6", "c7", "c8", "c9", "ca", "cb", "cc", "cd", "ce", "cf", "d0", "d1", "d2", "d3", "d4", "d5", "d6", "d7",
"d8", "d9", "da", "db", "dc", "dd", "de", "df", "e0", "e1", "e2", "e3", "e4", "e5", "e6", "e7", "e8", "e9",
"ea", "eb", "ec", "ed", "ee", "ef", "f0", "f1", "f2", "f3", "f4", "f5", "f6", "f7", "f8", "f9", "fa", "fb",
"fc", "fd", "fe", "ff"
};
// Convert binary data sequence [beginIt, endIt) to hexadecimal string
void dataToHexString(const uint8_t*const beginIt, const uint8_t*const endIt, string& str)
{
str.clear();
str.reserve((endIt - beginIt) * 2);
for(const uint8_t* it(beginIt); it != endIt; ++it)
{
str += s_hexTable[*it];
}
}
#7
5
I think there is a much simpler and more elegant solution. Some of the above-mentioned methods may even throw unhandled exceptions in some cases. Here is a fool-proof (as in never goes wrong) and very fast code. Just try it and compare the results in terms of speed and compactness:
我认为有一个更简单、更优雅的解决方案。有些方法甚至可能在某些情况下抛出未处理的异常。这里有一个万无一失的(如从未出错)和非常快的代码。试着把结果与速度和紧凑性进行比较:
#include <string>
// Convert string of chars to its representative string of hex numbers
void stream2hex(const std::string str, std::string& hexstr, bool capital = false)
{
hexstr.resize(str.size() * 2);
const size_t a = capital ? 'A' - 1 : 'a' - 1;
for (size_t i = 0, c = str[0] & 0xFF; i < hexstr.size(); c = str[i / 2] & 0xFF)
{
hexstr[i++] = c > 0x9F ? (c / 16 - 9) | a : c / 16 | '0';
hexstr[i++] = (c & 0xF) > 9 ? (c % 16 - 9) | a : c % 16 | '0';
}
}
// Convert string of hex numbers to its equivalent char-stream
void hex2stream(const std::string hexstr, std::string& str)
{
str.resize((hexstr.size() + 1) / 2);
for (size_t i = 0, j = 0; i < str.size(); i++, j++)
{
str[i] = (hexstr[j] & '@' ? hexstr[j] + 9 : hexstr[j]) << 4, j++;
str[i] |= (hexstr[j] & '@' ? hexstr[j] + 9 : hexstr[j]) & 0xF;
}
}
测试代码:
#include <iostream>
int main()
{
std::string s = "Hello World!";
std::cout << "original string: " << s << '\n';
stream2hex(s, s);
std::cout << "hex format: " << s << '\n';
hex2stream(s, s);
std::cout << "original one: " << s << '\n';
}
and the result is:
结果是:
original string: Hello World!
hex format: 48656C6C6F20576F726C6421
original one: Hello World!
#8
1
This will convert "Hello World" to "48656c6c6f20576f726c64" and will store this hex value in str1 and also will convert "48656c6c6f20576f726c64" to "Hello World".
这将把“Hello World”转换为“48656c6c6f20576f726c64”,并将此十六进制值存储在str1中,并将“48656c6c6f20576f726c64”转换为“Hello World”。
#include <iostream>
#include<sstream>
using namespace std;
int hexCharToInt(char);
string hexToString(string);
int main()
{
std::string str;
std::stringstream str1;
str="Hello World";
for(int i=0;i<str.length();i++){
str1 << std::hex << (int)str.at(i);
}
std::cout << str1.str() <<"\n";
string test = "48656c6c6f20576f726c64";
std::cout << hexToString(test) <<"\n";
return 0;
}
string hexToString(string str){
std::stringstream HexString;
for(int i=0;i<str.length();i++){
char a = str.at(i++);
char b = str.at(i);
int x = hexCharToInt(a);
int y = hexCharToInt(b);
HexString << (char)((16*x)+y);
}
return HexString.str();
}
int hexCharToInt(char a){
if(a>='0' && a<='9')
return(a-48);
else if(a>='A' && a<='Z')
return(a-55);
else
return(a-87);
}
#9
-1
Why has nobody used sprintf?
为什么没有人使用sprintf?
#include <string>
#include <stdio.h>
static const std::string str = "hello world!";
int main()
{
//copy the data from the string to a char array
char *strarr = new char[str.size()+1];
strarr[str.size()+1] = 0; //set the null terminator
memcpy(strarr, str.c_str(),str.size()); //memory copy to the char array
printf(strarr);
printf("\n\nHEX: ");
//now print the data
for(int i = 0; i < str.size()+1; i++)
{
char x = strarr[i];
sprintf("%x ", reinterpret_cast<const char*>(x));
}
//DO NOT FORGET TO DELETE
delete(strarr);
return 0;
}
#10
-1
This will convert Hello World to 48656c6c6f20576f726c64 and print it.
这将把Hello World转换为48656c6c6f20576f726c64并打印出来。
#include <iostream>
#include <cstring>
using namespace std;
int main()
{
char hello[20]="Hello World";
for(unsigned int i=0; i<strlen(hello); i++)
cout << hex << (int) hello[i];
return 0;
}
#1
64
A string like "Hello World" to hex format: 48656C6C6F20576F726C64.
像“Hello World”这样的字符串,以hex格式:48656C6C6F20576F726C64。
Ah, here you go:
啊,给你:
#include <string>
std::string string_to_hex(const std::string& input)
{
static const char* const lut = "0123456789ABCDEF";
size_t len = input.length();
std::string output;
output.reserve(2 * len);
for (size_t i = 0; i < len; ++i)
{
const unsigned char c = input[i];
output.push_back(lut[c >> 4]);
output.push_back(lut[c & 15]);
}
return output;
}
#include <algorithm>
#include <stdexcept>
std::string hex_to_string(const std::string& input)
{
static const char* const lut = "0123456789ABCDEF";
size_t len = input.length();
if (len & 1) throw std::invalid_argument("odd length");
std::string output;
output.reserve(len / 2);
for (size_t i = 0; i < len; i += 2)
{
char a = input[i];
const char* p = std::lower_bound(lut, lut + 16, a);
if (*p != a) throw std::invalid_argument("not a hex digit");
char b = input[i + 1];
const char* q = std::lower_bound(lut, lut + 16, b);
if (*q != b) throw std::invalid_argument("not a hex digit");
output.push_back(((p - lut) << 4) | (q - lut));
}
return output;
}
(This assumes that a char has 8 bits, so it's not very portable, but you can take it from here.)
(这假设一个字符有8位,所以它不是很便携,但您可以从这里获取。)
#2
26
string ToHex(const string& s, bool upper_case /* = true */)
{
ostringstream ret;
for (string::size_type i = 0; i < s.length(); ++i)
ret << std::hex << std::setfill('0') << std::setw(2) << (upper_case ? std::uppercase : std::nouppercase) << (int)s[i];
return ret.str();
}
int FromHex(const string &s) { return strtoul(s.c_str(), NULL, 16); }
#3
9
You can try this. It's Working...
你可以试试这个。它的工作…
#include <algorithm>
#include <sstream>
#include <iostream>
#include <iterator>
#include <iomanip>
namespace {
const std::string test="hello world";
}
int main() {
std::ostringstream result;
result << std::setw(2) << std::setfill('0') << std::hex << std::uppercase;
std::copy(test.begin(), test.end(), std::ostream_iterator<unsigned int>(result, " "));
std::cout << test << ":" << result.str() << std::endl;
}
#4
7
Simplest example using the Standard Library.
使用标准库的最简单的例子。
#include <iostream>
using namespace std;
int main()
{
char c = 'n';
cout << "HEX " << hex << (int)c << endl; // output in hexadecimal
cout << "ASC" << c << endl; // output in ascii
return 0;
}
To check the output, codepad returns: 6e
为了检查输出,codepad返回:6e。
and an online ascii-to-hexadecimal conversion tool yields 6e as well. So it works.
同时,一个在线的ascii-十六进制转换工具也能产生6e。所以它的工作原理。
You can also do this:
你也可以这样做:
template<class T> std::string toHexString(const T& value, int width) {
std::ostringstream oss;
oss << hex;
if (width > 0) {
oss << setw(width) << setfill('0');
}
oss << value;
return oss.str();
}
#5
7
Using lookup tables and the like works, but is just overkill, here are some very simple ways of taking a string to hex and hex back to a string:
使用查找表和类似的工作,但只是过度使用,这里有一些非常简单的方法,可以将字符串以十六进制和十六进制的形式返回到字符串:
#include <stdexcept>
#include <sstream>
#include <iomanip>
#include <string>
#include <cstdint>
std::string string_to_hex(const std::string& in) {
std::stringstream ss;
ss << std::hex << std::setfill('0');
for (size_t i = 0; in.length() > i; ++i) {
ss << std::setw(2) << static_cast<unsigned int>(static_cast<unsigned char>(in[i]));
}
return ss.str();
}
std::string hex_to_string(const std::string& in) {
std::string output;
if ((in.length() % 2) != 0) {
throw std::runtime_error("String is not valid length ...");
}
size_t cnt = in.length() / 2;
for (size_t i = 0; cnt > i; ++i) {
uint32_t s = 0;
std::stringstream ss;
ss << std::hex << in.substr(i * 2, 2);
ss >> s;
output.push_back(static_cast<unsigned char>(s));
}
return output;
}
#6
6
This is a bit faster:
这有点快:
static const char* s_hexTable[256] =
{
"00", "01", "02", "03", "04", "05", "06", "07", "08", "09", "0a", "0b", "0c", "0d", "0e", "0f", "10", "11",
"12", "13", "14", "15", "16", "17", "18", "19", "1a", "1b", "1c", "1d", "1e", "1f", "20", "21", "22", "23",
"24", "25", "26", "27", "28", "29", "2a", "2b", "2c", "2d", "2e", "2f", "30", "31", "32", "33", "34", "35",
"36", "37", "38", "39", "3a", "3b", "3c", "3d", "3e", "3f", "40", "41", "42", "43", "44", "45", "46", "47",
"48", "49", "4a", "4b", "4c", "4d", "4e", "4f", "50", "51", "52", "53", "54", "55", "56", "57", "58", "59",
"5a", "5b", "5c", "5d", "5e", "5f", "60", "61", "62", "63", "64", "65", "66", "67", "68", "69", "6a", "6b",
"6c", "6d", "6e", "6f", "70", "71", "72", "73", "74", "75", "76", "77", "78", "79", "7a", "7b", "7c", "7d",
"7e", "7f", "80", "81", "82", "83", "84", "85", "86", "87", "88", "89", "8a", "8b", "8c", "8d", "8e", "8f",
"90", "91", "92", "93", "94", "95", "96", "97", "98", "99", "9a", "9b", "9c", "9d", "9e", "9f", "a0", "a1",
"a2", "a3", "a4", "a5", "a6", "a7", "a8", "a9", "aa", "ab", "ac", "ad", "ae", "af", "b0", "b1", "b2", "b3",
"b4", "b5", "b6", "b7", "b8", "b9", "ba", "bb", "bc", "bd", "be", "bf", "c0", "c1", "c2", "c3", "c4", "c5",
"c6", "c7", "c8", "c9", "ca", "cb", "cc", "cd", "ce", "cf", "d0", "d1", "d2", "d3", "d4", "d5", "d6", "d7",
"d8", "d9", "da", "db", "dc", "dd", "de", "df", "e0", "e1", "e2", "e3", "e4", "e5", "e6", "e7", "e8", "e9",
"ea", "eb", "ec", "ed", "ee", "ef", "f0", "f1", "f2", "f3", "f4", "f5", "f6", "f7", "f8", "f9", "fa", "fb",
"fc", "fd", "fe", "ff"
};
// Convert binary data sequence [beginIt, endIt) to hexadecimal string
void dataToHexString(const uint8_t*const beginIt, const uint8_t*const endIt, string& str)
{
str.clear();
str.reserve((endIt - beginIt) * 2);
for(const uint8_t* it(beginIt); it != endIt; ++it)
{
str += s_hexTable[*it];
}
}
#7
5
I think there is a much simpler and more elegant solution. Some of the above-mentioned methods may even throw unhandled exceptions in some cases. Here is a fool-proof (as in never goes wrong) and very fast code. Just try it and compare the results in terms of speed and compactness:
我认为有一个更简单、更优雅的解决方案。有些方法甚至可能在某些情况下抛出未处理的异常。这里有一个万无一失的(如从未出错)和非常快的代码。试着把结果与速度和紧凑性进行比较:
#include <string>
// Convert string of chars to its representative string of hex numbers
void stream2hex(const std::string str, std::string& hexstr, bool capital = false)
{
hexstr.resize(str.size() * 2);
const size_t a = capital ? 'A' - 1 : 'a' - 1;
for (size_t i = 0, c = str[0] & 0xFF; i < hexstr.size(); c = str[i / 2] & 0xFF)
{
hexstr[i++] = c > 0x9F ? (c / 16 - 9) | a : c / 16 | '0';
hexstr[i++] = (c & 0xF) > 9 ? (c % 16 - 9) | a : c % 16 | '0';
}
}
// Convert string of hex numbers to its equivalent char-stream
void hex2stream(const std::string hexstr, std::string& str)
{
str.resize((hexstr.size() + 1) / 2);
for (size_t i = 0, j = 0; i < str.size(); i++, j++)
{
str[i] = (hexstr[j] & '@' ? hexstr[j] + 9 : hexstr[j]) << 4, j++;
str[i] |= (hexstr[j] & '@' ? hexstr[j] + 9 : hexstr[j]) & 0xF;
}
}
测试代码:
#include <iostream>
int main()
{
std::string s = "Hello World!";
std::cout << "original string: " << s << '\n';
stream2hex(s, s);
std::cout << "hex format: " << s << '\n';
hex2stream(s, s);
std::cout << "original one: " << s << '\n';
}
and the result is:
结果是:
original string: Hello World!
hex format: 48656C6C6F20576F726C6421
original one: Hello World!
#8
1
This will convert "Hello World" to "48656c6c6f20576f726c64" and will store this hex value in str1 and also will convert "48656c6c6f20576f726c64" to "Hello World".
这将把“Hello World”转换为“48656c6c6f20576f726c64”,并将此十六进制值存储在str1中,并将“48656c6c6f20576f726c64”转换为“Hello World”。
#include <iostream>
#include<sstream>
using namespace std;
int hexCharToInt(char);
string hexToString(string);
int main()
{
std::string str;
std::stringstream str1;
str="Hello World";
for(int i=0;i<str.length();i++){
str1 << std::hex << (int)str.at(i);
}
std::cout << str1.str() <<"\n";
string test = "48656c6c6f20576f726c64";
std::cout << hexToString(test) <<"\n";
return 0;
}
string hexToString(string str){
std::stringstream HexString;
for(int i=0;i<str.length();i++){
char a = str.at(i++);
char b = str.at(i);
int x = hexCharToInt(a);
int y = hexCharToInt(b);
HexString << (char)((16*x)+y);
}
return HexString.str();
}
int hexCharToInt(char a){
if(a>='0' && a<='9')
return(a-48);
else if(a>='A' && a<='Z')
return(a-55);
else
return(a-87);
}
#9
-1
Why has nobody used sprintf?
为什么没有人使用sprintf?
#include <string>
#include <stdio.h>
static const std::string str = "hello world!";
int main()
{
//copy the data from the string to a char array
char *strarr = new char[str.size()+1];
strarr[str.size()+1] = 0; //set the null terminator
memcpy(strarr, str.c_str(),str.size()); //memory copy to the char array
printf(strarr);
printf("\n\nHEX: ");
//now print the data
for(int i = 0; i < str.size()+1; i++)
{
char x = strarr[i];
sprintf("%x ", reinterpret_cast<const char*>(x));
}
//DO NOT FORGET TO DELETE
delete(strarr);
return 0;
}
#10
-1
This will convert Hello World to 48656c6c6f20576f726c64 and print it.
这将把Hello World转换为48656c6c6f20576f726c64并打印出来。
#include <iostream>
#include <cstring>
using namespace std;
int main()
{
char hello[20]="Hello World";
for(unsigned int i=0; i<strlen(hello); i++)
cout << hex << (int) hello[i];
return 0;
}