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- How do I use reflection to call a generic method? 7 answers
如何使用反射来调用泛型方法? 7个答案
I have a FindAll method on my DataAccessLayer which looks like this:
我的DataAccessLayer上有一个FindAll方法,如下所示:
public FindResult<T> FindAll<T>() where T : Entity, new()
and a client code that has a Type[] array which it needs to use to iteratively call the FindAll method with like this:
和一个客户端代码有一个Type []数组,它需要用来迭代调用FindAll方法,如下所示:
foreach (var type in typeArray)
{
var result = DataAccessLayer.FindAll<type>();
...
but the compiler complaints about "Type or namespace expected".. Is there an easy way to get around this? I've tried type.GetType() or typeof(type) and neither worked.
但编译器抱怨“预期的类型或命名空间”..有没有一种简单的方法来解决这个问题?我尝试过type.GetType()或typeof(type),但都没有用。
Many thanks in advance!
提前谢谢了!
2 个解决方案
#1
13
You may need to use Reflection to do this, something like this:
您可能需要使用Reflection来执行此操作,如下所示:
DataAccessLayer.GetType().GetMethod("FindAll<>").MakeGenericMethod(type).Invoke()
This blog post may also contain the information you need.
此博文可能还包含您需要的信息。
#2
3
When using generics, the type needs to be resolveable at compile time. You are trying to supply the type at runtime.
使用泛型时,类型需要在编译时解析。您正尝试在运行时提供该类型。
#1
13
You may need to use Reflection to do this, something like this:
您可能需要使用Reflection来执行此操作,如下所示:
DataAccessLayer.GetType().GetMethod("FindAll<>").MakeGenericMethod(type).Invoke()
This blog post may also contain the information you need.
此博文可能还包含您需要的信息。
#2
3
When using generics, the type needs to be resolveable at compile time. You are trying to supply the type at runtime.
使用泛型时,类型需要在编译时解析。您正尝试在运行时提供该类型。