I'm recently trying to build a custom UITableViewCell Class by adding a minor improved UITextField. I am also coding in swift 2 and I realised this error by recompiling the project in Xcode 7 beta. I initialised the array by call a custom init method.
我最近尝试通过添加一个次要改进的UITextField来构建自定义UITableViewCell类。我也在swift 2编码,我通过在Xcode 7 beta中重新编译项目来实现这个错误。我通过调用自定义init方法初始化了数组。
Heres is my Code:
Heres是我的代码:
INIT METHOD
INIT方法
init(dataObject: [NSManagedObject]!, objectAttributeValues: [String]!,placeholder: String!, segmentedControl: UISegmentedControl?) {
self.dataObject = dataObject
self.Placeholder.text = placeholder
self.objectAttributeValues = objectAttributeValues
if segmentedControl != nil {
self.segmentedControl = segmentedControl!
didHaveSegmentedControl = true
}
}
required init(coder aDecoder: NSCoder) {
fatalError("init(coder:) has not been implemented")
}
IBACTION EditingChanged
IBACTION EditingChanged
currentInputCount = "\(TextField.text)".characters.count
var indexOfArray: Int = 0
countOfRun = 0
if currentInputCount == 0 {
countOfRun = 0
formerInputCount = 0
editingDidEndForTextField = false
concatenedWord = []
Placeholder.text = ""
}
if !editingDidEndForTextField && currentInputCount > 0 {
while countOfRun < dataObject.count {
if !backspaceWasPressed() {
var arrayOfCharacters: [String] = []
if countOfRun <= dataObject.count - 1 {
for character in objectAttributeValues[countOfRun] {
let string = String(character)
arrayOfCharacters.append(string)
}
}
var convertedStringInFormOfArrayOfStrings: [String] = arrayOfCharacters
if currentInputCount == 1 {
concatenedWord.append(convertedStringInFormOfArrayOfStrings[currentInputCount-1])
}
else if countOfRun > 0 {
if objectAttributeValues[countOfRun].characters.count != concatenedWord[countOfRun].characters.count {
concatenedWord[countOfRun] = concatenedWord[countOfRun] + convertedStringInFormOfArrayOfStrings[currentInputCount-1]
}
}
countOfRun += 1
}
The error appears in line:
错误显示在行中:
for character in objectAttributeValues[countOfRun] {
I have no clue what it could be... Can anybody help me.
我不知道它可能是什么......任何人都可以帮助我。
Thank you a lot!
万分感谢!
2 个解决方案
#1
2
As of Swift 2, you can't simply loop over a String
to enumerate the characters anymore, now you have to call the characters
method on the String itself:
从Swift 2开始,你不能简单地遍历一个String来枚举字符,现在你必须在String本身上调用字符方法:
for letter in "hello".characters {
print(letter)
}
So for you, given that objectAttributeValues[countOfRun]
seems to return a String, that would be:
所以对你来说,假设objectAttributeValues [countOfRun]似乎返回一个String,那将是:
for character in objectAttributeValues[countOfRun].characters {
...
}
This is because String
does not conform to SequenceType
anymore in Swift 2.
这是因为String在Swift 2中不再符合SequenceType。
#2
-3
Like Eric said, as of Swift 2 you can no longer just go through a String like that.
就像埃里克所说,从Swift 2开始,你就不能再像这样经历一个字符串了。
In my opinion the easiest, and most likely the best programatically correct way to do this would be with a function.
在我看来,最简单,最可能最好的编程正确的方法是使用一个函数。
so
所以
func example(s: Int, str: String) -> Character {
var count = 0
for character in str {
if(count == s)
return character
count++
}
return " "
}
#1
2
As of Swift 2, you can't simply loop over a String
to enumerate the characters anymore, now you have to call the characters
method on the String itself:
从Swift 2开始,你不能简单地遍历一个String来枚举字符,现在你必须在String本身上调用字符方法:
for letter in "hello".characters {
print(letter)
}
So for you, given that objectAttributeValues[countOfRun]
seems to return a String, that would be:
所以对你来说,假设objectAttributeValues [countOfRun]似乎返回一个String,那将是:
for character in objectAttributeValues[countOfRun].characters {
...
}
This is because String
does not conform to SequenceType
anymore in Swift 2.
这是因为String在Swift 2中不再符合SequenceType。
#2
-3
Like Eric said, as of Swift 2 you can no longer just go through a String like that.
就像埃里克所说,从Swift 2开始,你就不能再像这样经历一个字符串了。
In my opinion the easiest, and most likely the best programatically correct way to do this would be with a function.
在我看来,最简单,最可能最好的编程正确的方法是使用一个函数。
so
所以
func example(s: Int, str: String) -> Character {
var count = 0
for character in str {
if(count == s)
return character
count++
}
return " "
}