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- Sorting an array of JavaScript objects 25 answers
- 排序JavaScript对象数组25个答案
I have an array of objects called canvasObjects
.
我有一个名为canvasObjects的对象数组。
Each object has an attribute called z
.
每个对象都有一个名为z的属性。
I want to sort this array based on objects z
. How do I do this using the sort()
method?
我想基于对象z对此数组进行排序。我如何使用sort()方法执行此操作?
3 个解决方案
#1
12
You just need to pass in a comparator to the sort function
您只需要将比较器传递给sort函数
function compare(a,b) {
if (a.attr < b.attr)
return -1;
if (a.attr > b.attr)
return 1;
return 0;
}
canvasObjects.sort(compare);
Or inline
或者内联
canvasObjects.sort(function(a,b) {return (a.attr > b.attr) ? 1 : ((b.attr > a.attr) ? -1 : 0);} );
See this POST
看到这个POST
#2
3
Tried other answers posted here but the I found the following to work best.
尝试在这里发布的其他答案,但我发现以下工作最好。
canvasObjects.sort(function(a,b) { return parseFloat(a.z) - parseFloat(b.z) } );
#3
0
Send anonymous function to the sort method which returns a subtraction of the property "z"
将匿名函数发送到sort方法,该方法返回属性“z”的减法
var arr = [{z:2},{z:4},{z:5},{z:1},{z:3}];
arr.sort(function(a,b) {return a.z - b.z});
above puts numbers in z to order 1,2,3,4,5. To reverse the order make it return "b.z - a.z".
在上面将数字放入z中以订购1,2,3,4,5。要颠倒顺序,请返回“b.z - a.z”。
#1
12
You just need to pass in a comparator to the sort function
您只需要将比较器传递给sort函数
function compare(a,b) {
if (a.attr < b.attr)
return -1;
if (a.attr > b.attr)
return 1;
return 0;
}
canvasObjects.sort(compare);
Or inline
或者内联
canvasObjects.sort(function(a,b) {return (a.attr > b.attr) ? 1 : ((b.attr > a.attr) ? -1 : 0);} );
See this POST
看到这个POST
#2
3
Tried other answers posted here but the I found the following to work best.
尝试在这里发布的其他答案,但我发现以下工作最好。
canvasObjects.sort(function(a,b) { return parseFloat(a.z) - parseFloat(b.z) } );
#3
0
Send anonymous function to the sort method which returns a subtraction of the property "z"
将匿名函数发送到sort方法,该方法返回属性“z”的减法
var arr = [{z:2},{z:4},{z:5},{z:1},{z:3}];
arr.sort(function(a,b) {return a.z - b.z});
above puts numbers in z to order 1,2,3,4,5. To reverse the order make it return "b.z - a.z".
在上面将数字放入z中以订购1,2,3,4,5。要颠倒顺序,请返回“b.z - a.z”。