用preg_replace替换ereg_replace

Hi need to change the function ereg_replace("[\]", "", $theData) to preg_replace

您需要将函数ereg_replace（“[\]”，“”，$ theData）更改为preg_replace

4 个解决方案

#1

To port ereg_replace to preg_replace you need to put the regex between a pair of delimiter

要将ereg_replace移植到preg_replace，您需要将正则表达式放在一对分隔符之间

Also your regx is [\] is invalid to be used for preg_replace as the \ is escaping the closing char class ]

另外你的regx [\]无法用于preg_replace，因为\正在逃避关闭的char类]

The correct port is

正确的端口是

preg_replace('/[\\\]/','',$theData)

Also since the char class has just one char there is no real need of char class you can just say:

此外，因为char类只有一个char，所以不需要char类，你只需说：

preg_replace('/\\\/','',$theData)

Since you are replace just a single char, using regex for this is not recommended. You should be using a simple text replacement using str_replace as:

由于您只更换一个char，因此不建议使用正则表达式。您应该使用str_replace使用简单的文本替换：

str_replace('\\','',$data);

#2

str_replace("\\","",$theData);

But I seriously doubt you need that replace at all. most likely you need some other operation.
What is this replace for?

但我严重怀疑你需要替换它。你很可能需要一些其他的操作。这个替换是什么？

#3

preg_replace("/\\\/", "", $theData);

#4

I used this sed to automatically replace ereg_replace by preg_replace and put the required slashes in. Assumes no \" in the first regex

我使用这个sed自动替换preg_replace的ereg_replace并将所需的斜杠放入。假设在第一个正则表达式中没有\“

 sed -i 's#ereg_replace("\([^"]*\)"#preg_replace("/\1/"#g' *.php

#1