如何用属性标记c#类以使其可串行化?

So I have a class. I want to make it serializable (into XML and back). I know how to use Xml.Linq to serialize.. but it is serialization via hand - not automated alike protobuf with its [ProtoContract] and other attributes when I mark up class and get it back and forward serializable.

所以我有一个班。我想使它可序列化(转换为XML和反XML)。我知道如何使用Xml。Linq序列化。但它是通过手工进行序列化的，而不是像protobuf那样使用它的[ProtoContract]和其他属性，当我标记类并让它返回并转发serializable时。

So I wonder ho waving

所以我不知道何朝我招手

public class Entries {
    public List<Entry> Entries {get; set;}
}

public class Entry {
    public string Id {get; set;}
    public string Path {get; set;}
}

get XML like:

XML:

<entries>
    <entry id="value" path="value"/>
</entries>

So how to mark up C# class with attributes to make it XML serializable?

那么如何用属性标记c#类以使其可序列化呢?

2 个解决方案

#1

You need to use attributes like [XmlRoot] and [XmlAttribute] for this. You can specify the XML element names as a parameter on the attributes.

为此需要使用[XmlRoot]和[XmlAttribute]等属性。可以将XML元素名称指定为属性上的参数。

See http://msdn.microsoft.com/en-us/library/system.xml.serialization.xmlrootattribute.aspx and the rest of the attributes in the namespace for the attributes you can use.

请参阅http://msdn.microsoft.com/en- us/library/system.xml.serializ.xmlroot.xmlrootattribute.aspx和名称空间中其他属性，以获取可以使用的属性。

#2

You need to add attributes to the class and class members that match your XML, for example: -

您需要向与您的XML匹配的类和类成员添加属性，例如:-

[Serializable]
[XmlRoot("RootNode")] 
public class Example
{
    [XmlElement("Foo")]
    public string Foo { get; set; }
    [XmlElement("Bar")]
    public string Bar { get; set; }
}

#1