I am trying to build a REST API with Spring.
我正在尝试使用Spring构建REST API。
How I can replace the URI
我如何替换URI
localhost: 8080 / rest / api / v1 / users / id ?id = 1
by
localhost: 8080 / rest / api / v1 / users / id / 1
1 个解决方案
#1
I succeeded in solve the problem using @PathVariable , example :
我成功地使用@PathVariable来解决问题,例如:
public ResponseEntity<String> hello (@PathVariable Integer id) {
String hello ="hello "+ id ;
return new ResponseEntity<String>(hello, HttpStatus.ACCEPTED);
}
and the corresponding URL is:
相应的URL是:
localhost:8080/hello/15
Tkx
#1
I succeeded in solve the problem using @PathVariable , example :
我成功地使用@PathVariable来解决问题,例如:
public ResponseEntity<String> hello (@PathVariable Integer id) {
String hello ="hello "+ id ;
return new ResponseEntity<String>(hello, HttpStatus.ACCEPTED);
}
and the corresponding URL is:
相应的URL是:
localhost:8080/hello/15
Tkx