How to display 10 latest jobs from database like this. Please click here to see image
如何从这样的数据库中显示10个最新作业。请点击这里查看图片
I have written following code so far not sure what to do next.
到目前为止,我编写了以下代码,不知道下一步该怎么做。
$query = "SELECT * FROM jobs ORDER BY posting_date DESC LIMIT 10";
$query = mysqli_query($conn, $query);
while ($row = mysqli_fetch_assoc($query) ) {
$job_title = row["job_title"];
$company_name = $row["company_name"];
$department = $row["department"];
$location = $row["location"];
$job_type = $row["job_type"];
$job_description = $row["job_description"];
$posting_date = date('d-m-y');
}
The $row returns all the columns from database. I want only four job title, company name, location and date
$ row返回数据库中的所有列。我只想要四个职称,公司名称,地点和日期
4 个解决方案
#1
1
Use column names in select query.
在选择查询中使用列名称。
$query = "SELECT job_title,company_name,location,posting_date FROM jobs ORDER BY posting_date DESC LIMIT 10";
$query = mysqli_query($conn, $query);
echo "<table>";
echo "<tr> <th>Job Title</th> <th>Company Name</th> <th>Location</th> <th>Date Posted</th> </tr>";
echo "<tbody>";
while($row = mysqli_fetch_assoc($query) ) {
$job_title = $row["job_title"];
$company_name = $row["company_name"];
$department = $row["department"];
$location = $row["location"];
$posting_date = date('d-m-y', strtotime($row['posting_date']));
echo "<tr>";
echo "<td>".$job_title."</td>";
echo "<td>".$company_name."</td>";
echo "<td>".$location."</td>";
echo "<td>".$posting_date."</td>";
echo "<tr>";
}
echo "</tbody>";
echo "</table>";
#2
0
Hmm change the query
嗯改变查询
$query = "SELECT job_title, company_name, location, posting_date FROM jobs ORDER BY posting_date DESC LIMIT 10";
#3
0
You can order by for rownum
您可以通过rownum订购
$query = "SELECT job_title, company_name, location, posting_date FROM jobs ORDER BY rownum DESC LIMIT 10";
#4
0
Here is an example how to build a htrml table with the 4 columns:
以下是如何使用4列构建htrml表的示例:
$query = "SELECT * FROM jobs ORDER BY posting_date DESC LIMIT 10";
$query = mysqli_query($conn, $query);
echo "<table>";
while ($row = mysqli_fetch_assoc($query) ) {
echo "<tr>";
echo "<td>$row['job_title']</td>";
echo "<td>$row['company_name']</td>";
echo "<td>$row['location']</td>";
echo "<td>$row['posting_date']</td>";
echo "<tr>";
}
echo "<table>";
#1
1
Use column names in select query.
在选择查询中使用列名称。
$query = "SELECT job_title,company_name,location,posting_date FROM jobs ORDER BY posting_date DESC LIMIT 10";
$query = mysqli_query($conn, $query);
echo "<table>";
echo "<tr> <th>Job Title</th> <th>Company Name</th> <th>Location</th> <th>Date Posted</th> </tr>";
echo "<tbody>";
while($row = mysqli_fetch_assoc($query) ) {
$job_title = $row["job_title"];
$company_name = $row["company_name"];
$department = $row["department"];
$location = $row["location"];
$posting_date = date('d-m-y', strtotime($row['posting_date']));
echo "<tr>";
echo "<td>".$job_title."</td>";
echo "<td>".$company_name."</td>";
echo "<td>".$location."</td>";
echo "<td>".$posting_date."</td>";
echo "<tr>";
}
echo "</tbody>";
echo "</table>";
#2
0
Hmm change the query
嗯改变查询
$query = "SELECT job_title, company_name, location, posting_date FROM jobs ORDER BY posting_date DESC LIMIT 10";
#3
0
You can order by for rownum
您可以通过rownum订购
$query = "SELECT job_title, company_name, location, posting_date FROM jobs ORDER BY rownum DESC LIMIT 10";
#4
0
Here is an example how to build a htrml table with the 4 columns:
以下是如何使用4列构建htrml表的示例:
$query = "SELECT * FROM jobs ORDER BY posting_date DESC LIMIT 10";
$query = mysqli_query($conn, $query);
echo "<table>";
while ($row = mysqli_fetch_assoc($query) ) {
echo "<tr>";
echo "<td>$row['job_title']</td>";
echo "<td>$row['company_name']</td>";
echo "<td>$row['location']</td>";
echo "<td>$row['posting_date']</td>";
echo "<tr>";
}
echo "<table>";